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igor_vitrenko [27]
3 years ago
9

I'm not sure of my answer I know that you have to multiply diagonally then add or subtract I'm not sure.

Mathematics
1 answer:
Dima020 [189]3 years ago
7 0
-18(1) = -18,right? 

4(3) = 12, right? 

-18 - 12 = -30

From the looks of it, we had to "Subtract" the outcome of each problem that we went over 

You're correct: -30 (option A.) would be your answer  

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Step-by-step explanation:

I didn't understand the question.

Do u want the function?

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y = ax  + b

at 0=0

at 1= 3

b = 0

at 1=3

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y = 3x

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6 0
2 years ago
How many solutions does an equation of the form x^2- k^2= 0 have?
N76 [4]
1. Use Difference of squares: a^2-b^2=(a+b)(a-b)
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3 years ago
(35 ÷ 5) - 5<br><br> show work!! help
saveliy_v [14]

Answer:

Step-by-step explanation:

(35/5) - 5

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6 0
2 years ago
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4 0
3 years ago
A car is driving away from a crosswalk. The formula d = t2 + 2t expresses the car's distance from the crosswalk in feet, d, in t
alukav5142 [94]

Answer:

8 feet per second.

Step-by-step explanation:

We have been given that a car is driving away from a crosswalk. The formula d=t^2+2t expresses the car's distance from the crosswalk in feet, d, in terms of the number of seconds, t, since the car started moving.

We will use average change formula to solve our given problem.

\text{Average change}=\frac{f(b)-f(a)}{b-a}

\text{Average change}=\frac{d(5)-d(1)}{5-1}

\text{Average change}=\frac{(5)^2+2(5)-((1)^2+2(1))}{4}

\text{Average change}=\frac{25+10-(1+2)}{4}

\text{Average change}=\frac{35-3}{4}\\\\\text{Average change}=\frac{32}{4}\\\\\text{Average change}=8

Therefore, the the car's average speed over the given interval of time would be 8 feet per second.

8 0
3 years ago
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