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Aleksandr [31]
3 years ago
13

If CP=Rs 500 and SP=550.find profit and profit percent%.

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0

Step-by-step explanation:

<h3><u>Give</u><u>n</u><u>:</u><u>-</u></h3>

CP=500

SP=550

<h3><u>To</u><u> </u><u>find</u><u>:</u><u>-</u></h3>

Profit and profit%

<h3><u>Solu</u><u>tion</u><u>:</u><u>-</u></h3>
  • CP =500
  • SP=550

We know that

\boxed{\sf Profit=SP-CP}

\\ \tt{:}\leadsto Profit=550-500

\\ \tt{:}\leadsto Profit=Rs.50

<h3>And</h3>

\boxed{\sf Profit\%=\dfrac{Profit}{CP}\times 100}

\\ \tt{:}\leadsto Profit\%=\dfrac{50}{500}\times{100}

\\ \tt{:}\leadsto Profit\%=\dfrac{50}{5}

\\ \tt{:}\leadsto Profit\%=10\%

\sf Key\:notes\begin{cases}\sf\mapsto CP=cost\: price \\ \sf \mapsto SP=Sold\:price\end{cases}

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How Much Have I Saved? Portfolio
avanturin [10]

The time value of money calculation can be performed using formula equations or online calculators.

The correct responses are;

  • 1) Option 3
  • 2) Option 2
  • 3) The difference in principal is approximately $8,000
  • The difference in interest earned is approximately $2,977.87
  • 4) It is better to invest more money at the beginning of the 30 years

Reasons:

Option 1: Present value = 0

Amount invested per month, A = $25/month

The Annual Percentage Rate, APR, r = 3.25%

Number of years = 30

The future value of an annuity is given by the formula;

\displaystyle FV_{A} = \mathbf{A \cdot \left (\frac{ \left(1 + \frac{r}{m} \right)^{m\cdot t} - 1}{\frac{r}{m} } \right)}

In option 1, m = 12 periods per year

Therefore;

\displaystyle FV_{A} = 25 \times \left (\frac{ \left(1 + \frac{0.0325}{12} \right)^{12 \times 30} - 1}{\frac{0.0325}{12} } \right) \approx  \mathbf{15,209.3}

Contribution = $25 × 12 × 30 = $9,000

Total interest earned = $15,209.3 - $9,000 = $6,209.3

Final balance = $15,209.3

Option 2: Present value = 0

Amount, A = $75/quarter

m = 4 periods per year

The Annual Percentage Rate, APR = 4.00%

Therefore;

The effective interest rate is therefore;

\displaystyle r_{eff} = \left(1 + \frac{0.04}{4} \right)^4 - 1 \approx \mathbf{0.04060401}

\displaystyle FV_{A} = 75 \times \left (\frac{ \left(1 + \frac{0.04060401}{4} \right)^{4 \times 30} - 1}{\frac{0.04060401}{4} } \right) \approx  17,437.7

Using an online calculator, FV = $17,467.04

Contribution = $75 × 4 × 30 = $9,000

Total interest earned = $17,467.04 - $9,000 = $8,467.04

Final balance = $17,467.04

Option 3: Present value = $1,000

APR = 6.25%

m = 12 period per year

Number of years, t = 30 years

Therefore;

\displaystyle FV = \left (1 + \frac{0.0625}{12} \right)^{12 \times 30} \approx \mathbf{6,489.17}

Contribution = $1,000

Total interest earned = $6,489.17 - $1,000 = $5,489.17

Final balance = $6,489.17

The table of values is therefore;

  • \begin{tabular}{|c|c|c|c|}Option \# &Contribution &Total Interest Earned&Final Balance\\1&\$9,000&\$6,209.3 & \$15,209.3\\2&\$9,000&\$8,467.04 &\$17,467.04\\3&\$1,000&\$5,489.17&\$6,489.17\end{array}\right]

1) The option that has the least amount invested are <u>option 3</u>

Option 3 investment plan is a present value of $1,000, invested for 30 years at 6.25% APR compounded monthly.

2) <u>Option 2</u> yielded the highest amount at the end of 30 years, given that the APR is higher than the APR for option 1, although the amount invested over the period are the same.

The basis of option 2 investment plan is $75 invested quarterly at 4.00% APR compounded monthly for 30 years.

3) The difference in the principal invested for the highest and lowest final balance is $9,000 - $1,000 = <u>$8,000</u>

The difference in the interest earned is; $8,467.04 - $5,489.17 = <u>$2,977.87</u>

4) In option 1 the present value is zero, therefore zero amount was invested at the beginning.

The interest to investment ration is 6,209.3:9,000 ≈ 0.7:1

In option 3, all the money was invested at the beginning.

The interest to investment ratio of option 3 is; 5,489.17:1,000 ≈ 5.5:1

Given that the interest to investment ratio, which is the return on investment is larger when more money is saved at the beginning as in option 3, <u>it is better to invest more money at the beginning</u>.

Learn more about future value of an annuity here:

brainly.com/question/8243704

3 0
3 years ago
I am a student in need pls help me
solmaris [256]

Answer:

2*400= 2*400*1

2*400

800

or

2 x 400 = 2 x 100 x 4

100 x 4

= 400

<u>I hope this helps:</u>

Sorry if it didn't :(

7 0
3 years ago
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There are 16 students who are participating in a chess tournament. The players will be randomly chosen. What is the probability
Ainat [17]
2/16 which is equal to 1/8 or 0.125
6 0
3 years ago
I'm not sure what this means, please help me I'll give you 10 points ;)
Karo-lina-s [1.5K]

<u>Answer:</u>

So all the possible solutions are:

  • \bold{523,~400,~379~and,~378.6}

<u />

<u>Solution Steps:</u>

<em>First you need to solve the real inequality to understand how to find the rest of the possible equations. </em>

<u>Add 78 to both sides:</u>

  • <u />78+78= Cancels Out
  • 300+78=378

<em>So now we know the real answer, but it ask for all possible answers. </em>

(Means anything larger than 300 when you plug it into x - 78 > 300.)

<u>Numbers that are greater than 378:</u>

  1.)  377-78=299 > 300  (False)

  2.)  523-78=445>300  (True)

  3.)  0-78=-78>300  (False)

  4.)  -62-78=-140>300  (False)

  5.)  400-78=322>300  (True)

  6.)  379-78=301>300  (True)

  7.)  222-78=144>300  (False)

  8.)  378.6-78=300.6>300 (True)

______________________________

 \bold{Hope~this~helps!}\\\bold{If~you~need~help~with~anything~else,~feel~free~to~ask!}\\\\\bold{~~~~~-TotallyNotTrillex}

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3 years ago
If the eyepiece of a compound microscope has a magnification power of 10X and the objective lense has a magnification power of 4
aleksandrvk [35]

Answer:

Total magnification of microscope at this setting is 40X

Step-by-step explanation:

Total magnification of microscope is determined by multiplying the magnification power of individual lenses.

So if eyepiece has magnification power of 10X and objective lense has magnification power of 4X , the total magnification of microscope would be

10 × 4 = 40

which means the object will appear 40 times larger than actual object.

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