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Thepotemich [5.8K]
3 years ago
12

given the function f(x) = 2^x, find the value of f−1(32). (1 point) f−1(32) = 0 f−1(32) = 1 f−1(32) = 5 f−1(32) = 16

Mathematics
1 answer:
EastWind [94]3 years ago
7 0

Answer:

5

Step-by-step explanation:

The inverse of f(x)=2^x is g(x)=\log_2(x).

g(32)=\log_2(32)

\log_2(32)=5 since 2^5=32.

g(32)=\log_2(32)=5

Note: In general, the inverse of f(x)=a^x is g(x)=\log_a(x).

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Given the graph below state whether or not the relation is a function, and give the domain and
Svetllana [295]

Answer:

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  • domain: [-2, 2]
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Step-by-step explanation:

A vertical line intersects the graph twice, so the relation is not a function. It is only allowed to intersect once if the relation is a function.

The domain is the horizontal extent, which is from -2 to +2.

The range is the vertical extent, which is -4 to +4.

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Answer:

x = -7 or x = 2/3

Step-by-step explanation:

I'm assuming you meant solve for x when f(x) = 0.

f(x) = 3x(x + 7) - 2(x + 7)

0 = (x + 7)(3x - 2) -- Both terms have a common factor of (x + 7) so we can group them

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Answer:

1) x < 0

2) x > 0

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4) x < -\frac{31}{55}

5) x \geq 0

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Step-by-step explanation:

1) -3 > 2x -3

2x- 3 < -3

2x - 3 + 3 < -3 +3

2x < 0

\frac{2x}{2} < \frac{0}{2}

x < 0

2) 5 > -x + 5

-x + 5 < 5

- x + 5 -5 < 5 - 5

-x < 0

\frac{-x}{-1} < \frac{0}{-1}

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3) \frac{x}{5} -2 < 0

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x - 10 < 0

x -10 + 10 < 0 +10

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4) -5x + 11 > 31

-5x \cdot 11 < 31

-55x < 31

\frac{-55x}{-55} > \frac{31}{-55}

x < -\frac{31}{55}

5) \frac{1}{2}x - 4 \geq -4

\frac{1}{2}x -4 +4 \geq -4 +4

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\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }

x \geq 0

6) -4x + 2 \leq 6

-4x +2 - 2 \leq 6 -2

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\frac{-4x}{-4} \leq  \frac{4}{-4}

x \geq -1

6 0
3 years ago
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