Answer:
7/9
Step-by-step explanation:
1 1/5 / 2 = 7/9 = 0.777
They want the radius of Venus. With this info you know that Earth is 6378.1 km and Venus is 326.1 km smaller than that. So you would subtract 326.1 from 6378.1 6378.1-326.1=6052 therefore 6052 km is your answer.
Answer:
Option D: is the function
Explanation:
Let the general form of quadratic equation be The function passes through the intercepts and and also passes though the point Substituting the points , and in the equation , we get, -----------(1) ----------(2) -----------(3)
Subtracting (1) and (2), we get, -----------(4)
Subtracting (2) and (3), we get, ------------(5)
Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,
Thus, the value of a is Substituting in equation (4), we get,
Thus, the value of b is Now, substituting the value of a and b in equation (1), we have,
Thus, the value of c is Now, substituting the value of a,b and c in the general formula , we get,
Taking out the common term as -2 we get,
Factoring , we get,
Thus, the function is
The Earth's circumference is 24,901 miles.
Assuming an apple is 3 inches wide:
3.7 trillion apples is 3/12/5280*3000000000000=142045454.545 miles.
That is 142045454.545/24901=5704.408 times around the Earth.
Answer:
<em>She need to subtract 7</em> from the left side to make a true equation again.
Step-by-step explanation:
The steps are given as:
suppose Malcolm adds 2 to the left side of an equation and subtracts 5 from the right side.
Now we are asked: What number should he now subtract from the left side to make a true equation again?
We know that if we apply any operation to one side of an equation than it must be applied to the other side as well in order to keep the statement true.
So now she need to subtract 7 from the left side to make a true statement.
( Because as she has subtracted 5 from the right.
and before that she has already added 2 to the left so now if she will subtract 7 from the left than the total change in the left will be: 2-7= -5 i.e. -5 is subtracted in the left which is equal to the operation applied to the right ).
