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boyakko [2]
3 years ago
14

What is 23475.9+387.15

Mathematics
2 answers:
asambeis [7]3 years ago
8 0
<span>23863.05 is the answer to the problem</span>
inn [45]3 years ago
5 0
Simply just add.

2   3  4  7  5  . 9

+
          3  8  7 .  1 5
_______________
   2  3 8 6 3  .  0   5
_______________


= 23 863.05 
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A certain positive number is multiplied by 4, and then the result is subtracted from the original number. The result is 21 less
stira [4]

Answer:

The number is 7

Step-by-step explanation:

certain positive number: x

x is multipled by 4:

4x

result of this is subtracted from the original number:

so original number minus 4x,

x - 4x

the result is 21 less than 0, this means negative 21

x - 4x = 0 - 21 = -21

do algebra:

-3x = -21

multiply both sides by -1

3x = 21

divide both sides by 3

x=7

(certain positive number: x) is equal to 7

4 0
3 years ago
Read 2 more answers
Simplify and Show Work or no brainlist
natali 33 [55]

Answer:

Step-by-step explanation:

and also you are diviing the numbers then subtracting 9

5 0
3 years ago
Read 2 more answers
How much is 1/9 of 3/8 (in lowest terms)?<br> A)4/17<br> B)03/17<br> C)1/36<br> D)1/24
mojhsa [17]

Answer:

1/24

Step-by-step explanation:

multiply 1/9 and 3/8. The product of the two factors is 3/ 72. Seeing the two factors on the other hand, we can cancel out 3. Hence the final answer to this problem in lowest terms becomes 1/24.

8 0
2 years ago
Can somebody help me?
Black_prince [1.1K]

Answer:

C) v≤-5

Step-by-step explanation:

4v\leq -20

Divide each side by 4,

v\leq -5

5 0
3 years ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same
san4es73 [151]

Answer:

Step-by-step explanation:

Z=\frac{x-mu}{\sigma }

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

Z=\frac{72-64}{2.7} =2.963

b) Y = 72"

z=\frac{72-69.3}{2.8} =0.965

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

Z<\frac{65-69.3}{2.8} =-1.536

e) X>73"

Z>\frac{73-64}{2.7} =3.33

Almost 0% can be taken

f) IQR =Q3-Q1

Z scores =

5 0
3 years ago
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