I don’t know if this will help but here you go
Step-by-step explanation:
MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]
WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)
SUBSTITUTING INTO THE EQUATION ABOVE
(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]
EQUATING THE X COORDINATES
=> 3 = (2+ X2)/2 (CROSS MULTIPLY)
=> 6 = 2 + X2
X(subscript 2)= 4
EQUATING THE Y COORDINATES
=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)
6 = –8 +Y2
=> Y(subscript 2)= 14
THEREFORE THE COORDINATES OF B ARE (4 ,14)
hope this helps :)
Answer: -3z+8
Step-by-step explanation: add -4z and z because they are like terms and then leave the 8 alone because it’s a term.
Answer:
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