The answer for this question is the last one
Monday = X
Tuesday = X + 3 (Problem says three more hours than he worked on Monday)
Wednesday = 2x + 1
(Problem says he worked 1 hour more than two times the number of hours on monday)
This side of the equation would be -
X + (X +3) + (2X + 1)
That's monday plus tuesday plus wednesday.
Then you would set up the other side of the equation.
This would be the total number of hours so it would be equal to monday, tuesday and wednesday combined.
2 + (5x)
Two hours more than five times the amount of Monday (X)
Now we put this together to have an equation
X + (X + 3) + (2x+ 1) = 2 + 5x
Now we need to collect like terms
4x + 4 = 2 + 5x
I just simplified the left side of the equation
Now I will subtract 4x from the left side to get all the variables on one side
4 = 2 + x
Now I subtract 2 to get the numbers both on one side
2 = x
So, Colby worked 2 hours on Monday.
Answer:
(identity has been verified)
Step-by-step explanation:
Verify the following identity:
tan(x)/sec(x) = sin(x)
Hint: | Eliminate the denominator on the left hand side.
Multiply both sides by sec(x):
tan(x) = ^?sec(x) sin(x)
Hint: | Express both sides in terms of sine and cosine.
Write secant as 1/cosine and tangent as sine/cosine:
sin(x)/cos(x) = ^?1/cos(x) sin(x)
Hint: | Come to a conclusion.
The left hand side and right hand side are identical:
Answer: (identity has been verified)
Well if it was 8 hours in the morning and 7 in the evening per day of the week it would be 105 divided by 2 for the number of sessions would equal to 52.5 sessions. if it was just that amount of time from that whole week, it would be 15 hours divided by 2 which would give you 7.5... Did that help?
