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Nesterboy [21]
3 years ago
14

1. The radius equals units 2. The diameter equals units

Mathematics
1 answer:
Lelu [443]3 years ago
8 0

Answer:

radius = 4units

diameter = 8units

Step-by-step explanation:

The radius is the distance from the midpoint of a circle to any point on the side of the circle. In this case, the radius is, 4units. The diameter is twice the radius and is 8 units.

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Can someone help me with this plz??
mamaluj [8]

Answer:

f(x) = -4x-1

f(7) = -(4)(7)-1

f(7) = -29

g(x) = 4x^2 - x

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g(-4) = 4(16) + 4

g(-4) = 64 + 4

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Let me know if this helps!

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The quantity of 7 less than x, multiplied by 4
laila [671]
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Your supervisor instructsyou to purchase 240 pensand 6 staplers for thenurse's station. Pens arepurchase in sets of 6 for$2.35 p
sveticcg [70]

Given:

Number of pen you are to purchase = 240 pens

Number of staplers you are to purchase = 6 staplers

Cost of pen in sets = 6 for $2.35

Cost of stapler in sets = 2 for $12.95

Let's find how much it will cost to purchase these products.

First find the average cost of each item:

\begin{gathered} \text{Average cost of pen = }\frac{2.35}{6} \\  \\ \text{Average cost of stapler = }\frac{12.95}{2} \end{gathered}

To find the total cost, we have the equation:

Total cost = (Average cost of pen x number of pens to be purchased) + (Avg cost of stapler x number of staplers to be purchased)

\text{Total cost = (}\frac{2.35}{6}\times240)+(\frac{12.95}{2}\times6)

Let's evaluate the equation:

\begin{gathered} \text{Total cost = (}\frac{2.35\times240}{6})+(\frac{12.95\times6}{2}) \\  \\ \text{Total cost = (}\frac{564}{6})+(\frac{77.7}{2}) \\  \\  \end{gathered}

Solving further:

\begin{gathered} \text{Total cost = (}94)+(38.85) \\  \\ \text{Total cost = }132.85 \end{gathered}

Therefore, the amount for purchasing these products will cost $132.85

ANSWER:

$132.85

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11 months ago
Find the form of the general solution of y^(4)(x) - n^2y''(x)=g(x)
Dennis_Churaev [7]

The differential equation

y^{(4)}-n^2y'' = g(x)

has characteristic equation

<em>r</em> ⁴ - <em>n </em>² <em>r</em> ² = <em>r</em> ² (<em>r</em> ² - <em>n </em>²) = <em>r</em> ² (<em>r</em> - <em>n</em>) (<em>r</em> + <em>n</em>) = 0

with roots <em>r</em> = 0 (multiplicity 2), <em>r</em> = -1, and <em>r</em> = 1, so the characteristic solution is

y_c=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}

For the non-homogeneous equation, reduce the order by substituting <em>u(x)</em> = <em>y''(x)</em>, so that <em>u''(x)</em> is the 4th derivative of <em>y</em>, and

u''-n^2u = g(x)

Solve for <em>u</em> by using the method of variation of parameters. Note that the characteristic equation now only admits the two exponential solutions found earlier; I denote them by <em>u₁ </em>and <em>u₂</em>. Now we look for a particular solution of the form

u_p = u_1z_1 + u_2z_2

where

\displaystyle z_1(x) = -\int\frac{u_2(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx

\displaystyle z_2(x) = \int\frac{u_1(x)g(x)}{W(u_1(x),u_2(x))}\,\mathrm dx

where <em>W</em> (<em>u₁</em>, <em>u₂</em>) is the Wronskian of <em>u₁ </em>and <em>u₂</em>. We have

W(u_1(x),u_2(x)) = \begin{vmatrix}e^{-nx}&e^{nx}\\-ne^{-nx}&ne^{nx}\end{vmatrix} = 2n

and so

\displaystyle z_1(x) = -\frac1{2n}\int e^{nx}g(x)\,\mathrm dx

\displaystyle z_2(x) = \frac1{2n}\int e^{-nx}g(x)\,\mathrm dx

So we have

\displaystyle u_p = -\frac1{2n}e^{-nx}\int_0^x e^{n\xi}g(\xi)\,\mathrm d\xi + \frac1{2n}e^{nx}\int_0^xe^{-n\xi}g(\xi)\,\mathrm d\xi

and hence

u(x)=C_1e^{-nx}+C_2e^{nx}+u_p(x)

Finally, integrate both sides twice to solve for <em>y</em> :

\displaystyle y(x)=C_1+C_2x+C_3e^{-nx}+C_4e^{nx}+\int_0^x\int_0^\omega u_p(\xi)\,\mathrm d\xi\,\mathrm d\omega

7 0
3 years ago
James had 42 dollars. He bought his sister a gift that costs x dollars. How much money does james have now, in terms of x
nata0808 [166]

Answer:

42-x = James' money now

Step-by-step explanation:

5 0
3 years ago
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