All categories

3 years ago

Draw a bar model that shows a pen is 4 times as long as an eraser that is 1 1/3 inches long.

Mathematics

1 answer:

timurjin [86]3 years ago

4 0

Answer:

Since, the length of one eraser = $1\frac{1}{3}\text{ Inches}=\frac{4}{3}$

Also, the length of one pen = 4 × the length of one eraser

$\text{The length of one pen} = 4\times \frac{4}{3}$

$=\frac{16}{3}=5\frac{1}{3}\text{ inches}$

Thus, the length of one pen is 16/3 inches.

Solution by the bar model :

Take 4 boxes representing the $1\frac{1}{3}\text{ inches}$ ,

Add the total value of the boxes

$= 1\frac{1}{3}+1\frac{1}{3}+1\frac{1}{3}+1\frac{1}{3}$

$= 1 + \frac{1}{3}+1 + \frac{1}{3}+1 + \frac{1}{3}+1 + \frac{1}{3}$

$=4 + \frac{4}{3}$

$=4 + 1 + \frac{1}{3}$

$= 5 + \frac{1}{3}$

$=5\frac{1}{3}\text{ inches }$

You might be interested in

Does this equation describe a linear function?<br> y = 2/X - 29

cupoosta [38]

Answeryes

Step-by-step explanation:

5 0

3 years ago

8:24 in simplest form

Mamont248 [21]

Answer:

1/3

Step-by-step explanation:

4 0

3 years ago

Type the correct answer in each box. A circle is centered at the point (5, -4) and passes through the point (-3, 2). The equatio

Galina-37 [17]

Answer:

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

Step-by-step explanation:

Given:

Center of circle is at (5, -4).

A point on the circle is $(x_1,y_1)=(-3, 2)$

Equation of a circle with center $(h,k)$ and radius 'r' is given as:

$(x-h)^2+(y-k)^2=r^2$

Here, $(h,k)=(5,-4)$

Radius of a circle is equal to the distance of point on the circle from the center of the circle and is given using the distance formula for square of the distance as:

$r^2=(h-x_1)^2+(k-y_1)^2$

Using distance formula for the points (5, -4) and (-3, 2), we get

$r^2=(5-(-3))^2+(-4-2)^2\\r^2=(5+3)^2+(-6)^2\\r^2=8^2+6^2\\r^2=64+36=100$

Therefore, the equation of the circle is:

$(x-5)^2+(y-(-4))^2=100\\(x-5)^2+(y+4)^2=100$

Now, rewriting it in the form asked in the question, we get

$(x+ \boxed{-5})^2+(y+\boxed4)^2=\boxed{100}$

4 0

3 years ago

Amelia is using substitution to determine if 8 is a solution to the equation. Complete the statements. 6a = 42 for a = 8 First,

Tju [1.3M]

Amelia must substitute 8 for the variable using parentheses. To simplify, Amelia must multiply 8 by 6. 8 is not a solution of the equation.

<h3>What is algebraic expression?</h3>

Algebraic expression are the expression which consist the variables, coefficients of variables and constants.

The algebraic expression are used represent the general problem in the mathematical way to solve them.

Amelia is using substitution to determine if 8 is a solution to the equation. The equation which is Amelia is solving for a = 8 is,

$6a = 42$

First, Amelia must substitute 8 for the variable using parentheses as,

$6(8) = 42$

To simplify, Amelia must. multiply 8 by 6.

$48 \neq 42$

The left hand side of the eqqation is not equal to the right hand side. Thus, 8 is not a solution of the equation.

Thus, Amelia must substitute 8 for the variable using parentheses. To simplify, Amelia must multiply 8 by 6. 8 is not a solution of the equation.

Learn more about the algebraic expression here;

brainly.com/question/2164351

4 0

2 years ago

Which of the b-values satisfy the following inequality?5 < b - 3Choose all the answers that apply: A.) b = 8B.) b = 9C.) b =

dusya [7]

[tex]\begin{gathered} \text{The inequality is,} \\ 5

4 0

1 year ago