Question

Draw a bar model that shows a pen is 4 times as long as an eraser that is 1 1/3 inches long.

Answer 1

Answer:

Since, the length of one eraser = $1\frac{1}{3}\text{ Inches}=\frac{4}{3}$

Also, the length of one pen = 4 × the length of one eraser

$\text{The length of one pen} = 4\times \frac{4}{3}$

$=\frac{16}{3}=5\frac{1}{3}\text{ inches}$

Thus, the length of one pen is 16/3 inches.

Solution by the bar model :

Take 4 boxes representing the  $1\frac{1}{3}\text{ inches}$,

Add the total value of the boxes

$= 1\frac{1}{3}+1\frac{1}{3}+1\frac{1}{3}+1\frac{1}{3}$

$= 1 + \frac{1}{3}+1 + \frac{1}{3}+1 + \frac{1}{3}+1 + \frac{1}{3}$

$=4 + \frac{4}{3}$

$=4 + 1 + \frac{1}{3}$

$= 5 + \frac{1}{3}$

$=5\frac{1}{3}\text{ inches }$