Answer:
D) 1/5 e 1/3
Step-by-step explanation:
You have the following quadratic equation:
(1)
In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

Then, the roots of the equation (1) are
D) 1/5 e 1/3
4x-1=18
4x=18+1
4x=19
x=19/4
Answer:
H0: μ = 7.8
Ha: μ > 7.8
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
For the case above;
Let μ represent the true mean length of long-distance calls after the rate reduction
The null hypothesis is that true mean length of long-distance calls after the rate reduction is the same and equal to 7.8 minutes
H0: μ = 7.8
The alternative hypothesis is that the true mean length of long-distance calls after the rate reduction have increased that is greater than 7.8 minutes
Ha: μ > 7.8
Hello from MrBillDoesMath!
Answer:
Choice C, sqrt(3-x)
Discussion:
Have no fear, MBill is here!
The quotient is
sqrt (9-x^2) / sqrt( 3+x) = => as sqrt(a)/sqrt(b) = sqrt(a/b), b <> 0
sqrt ( (9-x^2)/( 3+x) ) = => as 9 - x^2 = (3-x) * (3+x)
sqrt ( (3-x)(3+x) /(3+x) ) = => cancel (3+x) from num. and denom.
sqrt( 3-x)
This is Choice C
Note the domain restriction -3 < x < = 3 guarantees that division by zero can't happen.
Thank you,
MrB
The diagram is attached in the image