The graph of
... y = 3/4 - 2
is a horizontal line at y = -1.25.
The graph of
... y = (3/4)x - 2
is an upward-sloping line with a rise of 3 for every 4 units to the right. It intercepts the y-axis at y = -2.
Answer:
2 mm
Step-by-step explanation:
Let x be the sides of the original square,
then the area of the original square is x^2
The sides of the new square is x + 6
The area is (x + 6)^2
Then (x + 6)^2 = 16*x^2
Take square root on both sides and get
x + 6 = 4x,
3x = 6
so x = 2 mm
Vertex is (4,-3) and the axis of symmetry is X=4
The area of the shaded region is
.
Solution:
Given radius = 4 cm
Diameter = 2 × 4 = 8 cm
Let us first find the area of the semi-circle.
Area of the semi-circle = 


Area of the semi-circle =
cm²
Angle in a semi-circle is always 90º.
∠C = 90°
So, ABC is a right angled triangle.
Using Pythagoras theorem, we can find base of the triangle.




cm
Base of the triangle ABC =
cm
Height of the triangle = 4 cm
Area of the triangle ABC = 

Area of the triangle ABC =
cm²
Area of the shaded region
= Area of the semi-circle – Area of the triangle ABC
= 
= 
Hence the area of the shaded region is
.