I think this is the Transitive postulate of equality.
Personally I can't see much point in giving labels to these equalities.
I don’t understand please put it in a form i could possibly understand
Answer:
3(2x^2-3x+14)
Step-by-step explanation:
6x^2-9x+42
All three terms have a common factor of 3
3(2x^2-3x+14)
Now let's focus on 2x^2-3x+14 and bring down the factor 3 later
so a=2
b=-3
c=14
Let's try to find two factors for ac that multiply to be a*c and add up to be b.
ac=28
b=-3
-----
ac=7(4)=14(2)=8(2)
Even if I made these pairs with both negatives nothing would give me -3
So you can only go as far as 3(2x^2-3x+14)
Here is another thing to help you if you have ax^2+bx+c and b^2-4ac<0 then it can't be factored (over reals)
The answer is the first one because 4 feet 5 inches times 40 is 176 feet and 8 inches
25% is equal to 1/4 so that means 90 is 1 out of 4 peaces of that number so you are ganna want to multiplay 90 X 4 to get your answer
