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adoni [48]
3 years ago
6

What is the z score associated with 75 percentile

Mathematics
1 answer:
ddd [48]3 years ago
6 0

Answer:

First, determine how many standard deviations above the mean one would have to be to be in the 75th percentile. This can be found by using a z table and finding the z associated with 0.75. The value of z is 0.674. Thus, one must be .674 standard deviations above the mean to be in the 75th percentile

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Margaret is planning a wedding reception. She wants to spend less than her budget of $5,748, and Margaret has already spent $2,4
noname [10]

Answer:

She can invite 109 guests and be right on top of budget. If she wants to spend less than her budget though she can only invite 108 people.

Step-by-step explanation:

First you have to subtract 5,748 - 2,478 which is 3270. Next you have to divide 3270 by 30 because each person costs 30 dollars. 3270 divided by 30 is 109.

I hope this helps! Please mark me brainliest if I am correct! Have a nice day!

6 0
3 years ago
Seven is reading a book while on vacation. So far, he has read 1/6 of the book. He wants to finish 3/6 of the book by the end of
SOVA2 [1]

Answer:

She has to read 2/6 more by the end of her vacation if she wants to finish 3/6 (1/2) of the book.

Step-by-step explanation:

If this wasn't the answer you were looking for please tell me so I can redo it.

4 0
3 years ago
Read 2 more answers
A car requires 22 litres of petrol to travel a distance of 259.6 km.Find
Anon25 [30]

Answer:

Step-by-step explanation:

1. A car requires 22 litres of petrol to travel a distance of 259.6 km

what is the distance that the car can travel on 63 ltr of petrol

22ltr = 259.6km

63ltr=

cross multiply

{63 x 259.6}/22 = 16354.8/22 = 743.4 km

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km

2. To travel a distance of 2013.2 km

we would need to calculate the amount of fuel

A car requires 22 litres of petrol to travel a distance of 259.6 km

what amount of fuel would it require to travel 2013.2km

22ltr = 259.6km

xltr = 2013.2km

x is the value of petrol to cover 2013.2km

cross multiply

(2013.2 x 22)/259.6

44290.4/259.6 = 170.610169492≈170.6 ltr

A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km

if 1ltr is $1.99

170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5

The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5

5 0
3 years ago
Factor the expression completely. 6×3- 4×2 – 16x A. 0 B. 2x(3×2 – 2x – 8) C. 2x(3x + 4)(x – 2) D. 4x(2x + 1)(x – 4) E. 2x(2×2 +
Ghella [55]

Answer:

<h3>The answer is option C</h3>

Step-by-step explanation:

6x³ - 4x² - 16x

To factorize the expression first factor out the GCF out

The GCF in the expression is 2x

That's

2x( 3x² - 2x - 8)

Next Factorize the terms in the bracket

To factorize write - 2x as a difference

that's

2x( 3x² + 4x - 6x - 8)

<u>Factor out x from the expression</u>

2x [ x( 3x + 4) - 6x - 8 ]

<u>Next factor out - 2 from the expression</u>

2x [ x ( 3x + 4) - 2( 3x + 4) ]

<u>Factor out 3x + 4 from the expression</u>

We have the final answer as

<h3>2x( 3x + 4)( x - 2)</h3>

Hope this helps you

4 0
3 years ago
Question 4) -6x + 9 + 6x -13<br> Your answer<br> Question 5) 8x - 9 -11 -14x<br> Your answer
Digiron [165]

Answer:

4) -4

5) -6x-20

Step-by-step explanation:

Add x with x's and numbers with numbers

4) -6x + 9 + 6x -13

-6x+6x+9-13

x's cancel

9-13 = -4

5) 8x - 9 -11 -14x

8x-14x-9-11

-6x-20

hope this helps

3 0
2 years ago
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