Answer:
Please Find the solution below
Step-by-step explanation:
Let us say the two equations are
x+y=5 --------------(A)
x-y=1 -------------(B)
Let us solve them for x and y by adding them
2x=6
x=3
Hence from (A)
3+y=5
y=2
Hence our solution is
x=3, y=2
Adding same number to equation (A) say 2 we get
x+y+2=5+2
x+y=5+2-2
x+y=5
Hence equation remains the same while adding same number to each side.
Same thing happens if we add same number to equation (B)
Hence we draw the conclusion that the solution remains the same if same number is added to each side of the original equation.
ANSWER:
Let t = logtan[x/2]
⇒dt = 1/ tan[x/2] * sec² x/2 × ½ dx
⇒dt = 1/2 cos² x/2 × cot x/2dx
⇒dt = 1/2 * 1/ cos² x/2 × cosx/2 / sin x/2 dx
⇒dt = 1/2 cosx/2 / sin x/2 dx
⇒dt = 1/sinxdx
⇒dt = cosecxdx
Putting it in the integration we get,
∫cosecx / log tan(x/2)dx
= ∫dt/t
= log∣t∣+c
= log∣logtan x/2∣+c where t = logtan x/2
Answer:
The correct answer is !40 cows and 28 Horses
Step-by-step explanation:
h+5h=168
6h=168
h=168/6
h=28 horses.
5*28=140 cows.
Proof:
28=140=168
168=168
Answer:
The answer is the forth one , Y-8+2⩽-2+2
The car will travel eighty miles in 1/2 hour
