The smallest of two integers is 61
Step-by-step explanation:
Let x be the smaller integer
Then the next integer will be:
x+1
According to given statement that the sum of both is 123
Subtracting 1 from both sides
Dividing both sides by 2
The smallest of two integers is 61
Keywords: Linear equations, Variables
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For this question you should know that you can multiply both number in 1/4 by 3 and you will have:
1*3 / 4*3 = 3/12
so the answer is yes they are equivalent :)))
i hope this is helpful
have a nice day
There are two choices for each child: overweight (o) or underweight (u). So if the first child is o the next can be o or u. If the first is u the second can be o or u. This gives four possibilities. Here the first child is the letter noted first and the second is the one listed second:
OO
OU
UO
UU
There are 4 outcomes and if each is equally likely then the probability of each is 1/4. Thus the probability of UU is 1/4
The probability of one underweight and one over weight is 1/2 because in two of the outcomes listed above there is one O and one U (namely OU and UO). Since there are 4 outcomes the probability is 2/4 = 1/2
Answer:
-2
Step-by-step explanation:
3n+2n+4=9n+12
5n+4=9n+12
5n-9n=-4+12
-4n=8
n=8/-4
n= -2
