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Fittoniya [83]
3 years ago
10

Cube root 343 ^-3/ root 4 81

Mathematics
1 answer:
zlopas [31]3 years ago
7 0

Answer:

$\frac{1}{1029} $

Step-by-step explanation:

$\frac{\sqrt[3]{343^{-3}}}{\sqrt[4]{81} }  $

$\boxed{\text{Property: } a^{-b}=\frac{1}{a^{b}}} $

$\frac{\sqrt[3]{\frac{1}{343^{3}} }}{\sqrt[4]{81} }  $

$\frac{\frac{\sqrt[3]{1} }{\sqrt[3]{343^3} } }{\sqrt[4]{81} }  $

$\frac{\frac{1 }{343} }{3}  $

$\frac{342 \cdot \frac{1 }{343} }{343 \cdot 3}  $

$\frac{1}{1029} $

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r=-6

Step-by-step explanation:

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3. The Leakey Shipping Company uses small containers with a volume of 2.5 m3and large containers with a volume of 4 m3. A shipme
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Given:

• Volume of small containers = 2.5 m³

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• Volume of large containers = 4 m³

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Let's find the number of the size of each container used.

Let s represent the number of small containers

Let L represent the number of large containers.

• Equation for number of containers:

s + L = 140

• Equation for total volume:

2.5s + 4L = 140

Hence, we have the set of equations:

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2.5s + 4L = 440...................equation 2

Let's solve the set of equations simultaneously using substitution methos.

Rewrite equation 1 for L:

L = 140 - s...........................equation 3

Substitute (140 -s) for L in equation 2:

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2.5s + 560 - 4s = 440

Combine like terms:

2.5s - 4s + 560 = 440

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Divide both sides by -1.5:

\begin{gathered} \frac{-1.5s}{-1.5}=\frac{-120}{-1.5} \\  \\ s=80 \end{gathered}

Substitute 80 for s in either of the equations.

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L = 140 - s

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