Answer:
n the figure, m 3 = 75 and mZ10 = 115. ... CY 337] . 2x +13269. 2x =50. X=28. Find mZ1 in each figure. Exoor. 10. تا ... m24 = 75 24 and 22 are vertical angles.
Missing: m22 = | Must include: m22 =
Step-by-step explanation:
Answer:
See explanation
Step-by-step explanation:
1. Given the expression
![\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%20%7D)
Note that
![\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E5%7D%3Dx%5E%7B%5Cfrac%7B5%7D%7B7%7D%7D%20%5C%5C%20%5C%5C%5Csqrt%5B4%5D%7Bx%5E2%7D%3Dx%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
When dividing
by
we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

and the result is ![x^{\frac{3}{14}}=\sqrt[14]{x^3}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B3%7D%7B14%7D%7D%3D%5Csqrt%5B14%5D%7Bx%5E3%7D)
2. Given equation ![3\sqrt[4]{(x-2)^3} -4=20](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%3D20)
Add 4:
![3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%2B4%3D20%2B4%5C%5C%20%5C%5C3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%3D24)
Divide by 3:
![\sqrt[4]{(x-2)^3} =8](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20%3D8)
Rewrite the equation as:

Hence,

-6x-13y
2x+(3x2)-14x+(3x2)+12x+(3x2)-12x+(3x2)-12x+(3x2)-12x
2x+6x-14x+6x+12x+6x-12x+6x-12x+6x-12x=-6
-6y+7y+1y-1y+1y-13y=-13y
if a letter is by itself then there is automatically a one in front of it
What quotients did they get because the answer is 40
The last statement
AD and DC are equal as shown by the small lines through them
DB is perpendicular and at exactly half way of line AC
Angles CBD and ADB are 92° and 88°
92 + 88 = 180
So the false one must be the last one.