You know 1 is not a root because the sum of the coeffcients of the equation is 14, not zero.
It is fairly easy to try 3 by synthetic division (see attachment), which tells you that 3 is a root and the remaining quadratic factor is x²-3x-5. The quadratic formula tells you the roots of that factor are
... x = (-b±√(b²-4ac))/(2a) = (3±√29)/2
The appropriate choices are
... C. (3-√29)/2
... D. (3+√29)/2
... F. 3
_____
The quadratic formula tells you the solution to
... ax²+bx+c=0
is x = (-b±√(b²-4ac))/(2a)
We have a=1, b=-3, c=-5.
Answer:
<u><em>There are 45 1/5ths in 9</em></u>
Step-by-step explanation:
1/5 = 5
5 * 9 = 45
<u><em>45</em></u>
<u><em></em></u>
It will be
(-2)^2+4*(-3)(-3) =40
Answer:
-2
Step-by-step explanation:
Hey there!!
if we evaluate the expression it will look like :
3x + 14 = 8
and if we solve it:
3x+14=8
Step 1: Subtract 14 from both sides.
3x+14−14=8−14
3x=−6
Step 2: Divide both sides by 3.
3x/3 = -6/3
x= −2
Answer:

Step-by-step explanation:
To make d the subject of formula, we need to rearrange the equation such that we arrive at d= _____.

<em>Remove the fraction by multiplying (d +3) on both sides:</em>

<em>Expand</em><em>:</em>
<em>
</em>
<em>Bring</em><em> </em><em>all</em><em> </em><em>the</em><em> </em><em>d</em><em> </em><em>terms</em><em> </em><em>to</em><em> </em><em>one</em><em> </em><em>side</em><em> </em><em>and</em><em> </em><em>move</em><em> </em><em>the</em><em> </em><em>others</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>other</em><em> </em><em>side</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>equation</em><em>:</em>

<em>Factorise</em><em> </em><em>d</em><em> </em><em>out</em><em>:</em>
<em>
</em>
<em>Divide</em><em> </em><em>by</em><em> </em><em>(</em><em>c</em><em> </em><em>+</em><em>1</em><em>)</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>:</em>
<em>
</em>