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tankabanditka [31]
3 years ago
13

Cards bearing numbers 1,3,5..35 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a car

d bearing
(a) a prime number less than 15
(b) a number divisible by 3 and 5
Mathematics
1 answer:
Amanda [17]3 years ago
3 0
<h2>Answer:\dfrac{6}{35} ,\dfrac{2}{35}</h2>

Step-by-step explanation:

probability=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}

Question a:

Number of prime numbers less than 15 are 2,3,5,7,11,13.

There are 6 favourable outcomes.

There are 35 total outcomes.

probability=\frac{6}{35}

Question b:

Numbers divisible divisible by 3 and 5 are 15,30

There are 2 favourable outcomes.

There are 35 total outcomes.

probability=\frac{2}{35}

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Answer:

y = (1/8)x

Step-by-step explanation:

The relevant basic formula is y = kx, where k is the constant of proportionality.

We must find k.  To do this, let y = 15/6 and x = 20 in the above formula:

15/6 = k(20)

We solve for k by dividing both sides by 20:  15/(6*20) = k = 1/8

Then the specific formula for this situation is y = (1/8)x

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Assume the hold time of callers to a cable company is normally distributed with a mean of 5.5 minutes and a standard deviation o
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Answer:

The percent of callers are 37.21 who are on hold.

Step-by-step explanation:

Given:

A normally distributed data.

Mean of the data, \mu = 5.5 mins

Standard deviation, \sigma = 0.4 mins

We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.

Lets find z-score on each raw score.

⇒ z_1=\frac{x_1-\mu}{\sigma}   ...raw score,x_1 = 5.4

⇒ Plugging the values.

⇒ z_1=\frac{5.4-5.5}{0.4}

⇒ z_1=-0.25  

For raw score 5.5 the z score is.

⇒ z_2=\frac{5.8-5.5}{0.4}  

⇒ z_2=0.75

Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.

We have to work with P(5.4<z<5.8).

⇒ P(5.4

⇒ P(-0.25

⇒ P(z

⇒ z(1.5)=0.7734 and z(-0.25)=0.4013.<em>..from z -score table.</em>

⇒ 0.7734-0.4013

⇒ 0.3721

To find the percentage we have to multiply with 100.

⇒ 0.3721\times 100

⇒ 37.21 %

The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21

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