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ValentinkaMS [17]
3 years ago
8

Jenny is planning an extended trip to Russia.The table below shows a list of cities which she would like to visit during her sta

y, along with the amount of money she anticipates needing to spend on travel, lodging, and similar expenses in each city. All costs are given in Russian rubles (RUB).
City
Cost (RUB)
Izhevsk
4,721
Novosibirsk
4,870
Nizhny Novgorod
6,920
Moscow
5,485
Chelyabinsk
5,217
Saint Petersburg
5,960
Tolyatti
5,598
Yaroslavl
4,901

Even though Jenny wants to go to each of these cities, her budget is only RUB 33,000, so she recognizes that she must change her itinerary and choose not to visit some cities. Which of the following pairs of cities will not put Jenny back under budget if she drops them?
a.
Moscow and Chelyabinsk
b.
Izhevsk and Nizhny Novgorod
c.
Novosibirsk and Saint Petersburg
d.
Yaroslavl and Tolyatti

THE ANSWER IS D. YAROSLAVI AND TOLYATTI

EXPLANATION: the total of all cities is 43,672. If we subtract 4901 for Yaroslavi and 5598 for Tolyatti we have 33,173 (43,672 - 4901 - 5598 = 33,173). This would still be over Jenny's budget
Mathematics
2 answers:
densk [106]3 years ago
8 0

The correct answer is D hope this helps you.

snow_lady [41]3 years ago
3 0

Answer:

<u>d. Yaroslavl and Tolyatti</u>

Step-by-step explanation:

<u>Correct answer is </u><u>D</u><u> on </u><u>EDGE. Hope this helps! :)</u>

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BARSIC [14]

Answer:

<u>The correct answer is 1/35 (fully simplified fraction)</u>

Step-by-step explanation:

Number of slips of paper in the bag = 15

Number of slips of paper in the bag that are a multiple of 4 = 3 (those numbered 4, 8 and 12)

Using Laplace Rule, that states that the probability of an event X is obtained by dividing the number of results that form event X by the number of possible outcomes, provided that the elementary events are equiprobable, that is, that all possible outcomes have the same probability.

Probability of pulling a 1st piece of paper multiple of 4 = 3/15 = 1/5

Now we have a second event Y that is not independent from the first event X, because now the number of slips is 14 and not 15, you're not returning the first slip of paper.

Probability of pulling a 2nd piece of paper multiple of 4 = Probability of the 1st event * probability of the 2nd event after it happened the 1st one

Probability of pulling a 2nd piece of paper multiple of 4 = 1/5 * 2/14

Probability of pulling a 2nd piece of paper multiple of 4 = 2/70 = 1/35

<u>The probability of pulling two slips of paper both numbered with a multiple of 4 is 1/35.</u>

3 0
3 years ago
The black graph is the graph of y=f(x). Choose the equation for the red graph.<br> Please help!!
yan [13]

Answer:

B

Step-by-step explanation:

The black graph is the graph of y=f(x).

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A. y=f(x-1) determines the translation of the graph y=f(x) one unit to the right.

B. y=f\left(\dfrac{x}{-1}\right) determines the reflection of the graph y=f(x) across the y-axis.

C. y-1=f(x),\ y=f(x)+1 determines the translation of the graph y=f(x) one unit up.

D. \dfrac{y}{-1}=f(x),\ y=-f(x) determines the reflection of the graph y=f(x) across the y-axis.

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3 years ago
If R is the total resistance for a parallel circuit with two resistors of resistances of r1 and r2 then 1/r=1/r1+1/r2 find the r
Allushta [10]
A little Algebra, and we're home free!

We are given R = 20 and r2 = 75. We need to find r1.

The formula is 1/R = 1/r1 + 1/r2. Plug-in:
1/20 = 1/r1 + 1/75
1/20 - 1/75 = 1/r1
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r1 = 1/0.03666
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Our answer is r1 = 27 ohms.
6 0
3 years ago
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Her IRA interest at the end of 30 years is mathematically given as

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brainly.com/question/5160341

6 0
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A number increased by 9 is 13
Alborosie

Answer:

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6 0
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