Answer:
The total surface area of triangular pyramid is 172 cm squared
Step-by-step explanation:
Triangular pyramid:
- Number of faces 4.
- Number of vertices of a triangular pyramid is 6.
- The volume is
. A= area of the pyramid's base and H= height of the pyramid.
- The surface area of triangular pyramid B+L. B= area of base, L= area of lateral surface.
Given that, the area of the base is 43 cm squared. Lateral faces with bases of 10 cm and heights 8.6 cm.
The 3 sides of the triangular pyramid is triangle in shape.
The area of triangle is
.
The lateral surface area of the triangular pyramid is

cm squared
=129 cm squared
The total surface area of triangular pyramid is
=Area of the base + lateral surface area
=(43+129) cm squared
=172 cm squared
The answer is C.50. That is the answer.
A.P. series would be: 201, 204, 207 .... 597
Here, a = 201, d = 3, l = 597
Now, l = a + (n - 1) d
597 = 201 + (n - 1)3
597 - 201 = 3n - 3
396 + 3 = 3n
n = 399/3
n = 133
In short, Your Answer would be 133
Hope this helps!
Answer:
A 17
B 11.5
Step-by-step explanation:
5+2=7+2=9+2=11+2=13+2=15+2=17
and please check ur question C and D
That function is incorrect.
The correct function is . . . . C(f) = (5/9) (f - 32) .
If a Fahrenheit thermometer reads 52° ,
then a Celsius thermometer should read . . .
C (52) = (5/9) (52 - 32) =
(5/9) (20) = <em>(11 and 1/9)°C</em>.