What is the sum? (1/x+2)+(1/x+3)+(1/X^2+5+6)
1 answer:
For this case we have the following expression: (1 / x + 2) + (1 / x + 3) + (1 / X ^ 2 + 5 + 6) Rewriting we have: (1 / x + 2) + (1 / x + 3) + (1 / ((x + 2) * (x + 3))) By doing common factor we have: (1 / ((x + 2) * (x + 3))) * (x + 3 + x + 2 + 1) Rewriting: (1 / ((x + 2) * (x + 3))) * (2x + 6) The sum is: ((2x + 6) / ((x + 2) * (x + 3))) Answer: ((2x + 6) / ((x + 2) * (x + 3)))
You might be interested in
y= -5-x
-x + 5(-5-x) = -7
-x -25-5x =-7
-x-5x = 25 -7
-6x= 18
x = -3
-3 +y = -5
y= -5 +3
=-2
-(-3) + 5(-2)
3 - 10 = -7
Answer: 2
Step-by-step explanation:
The answer is B. (2 + x) + 3y. The associative change happened when they just moved the parenthesis. Hope this helps!
The Pythagorean theorem is the square of the length hypotenuse side of a right triangle equals the sum of the squares of the lengths of the other 2 sides. <span />