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3 years ago

8.3333 times the square root of 144

Mathematics

1 answer:

Svet_ta [14]3 years ago

3 0

The square root of 144 is 12. So multiply 8.3333 by 12. You should get 99.9996.

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What is 525/1000 in simplest form?

KiRa [710]

525/1000 = 105/200 = 21/40

8 0

3 years ago

I have 7 hundreds blocks, 5 tens blocks, and 8 ones blocks. I use my blocks to model two 3-digit numbers. What could my two numb

lawyer [7]

There 7 blocks of hundreds which means each such block is equivalent to 100.
There are 5 blocks of tens, which means each such block is equivalent to 10.
There are 8 blocks of ones, which means each such block is equivalent to 1.

The total of these blocks will be = 7(100) + 5(10) + 8(10) = 758

We can make several two 3-digit numbers from these blocks. An example is listed below:

Example:
Using 3 hundred block, 2 tens blocks and 4 ones block to make one number and remaining blocks to make the other number. The remaining blocks will be 4 hundred blocks, 3 tens blocks and 4 ones blocks
The two numbers we will make in this case are:

1st number = 3(100) + 2(10) + 4(1) = 324
2nd number = 4(100) + 3(10) + 4(1) = 434

The sum of these two numbers is = 324 + 434 = 758
i.e. equal to the original sum of all blocks.

This way changing the number of blocks in each place value, different 3 digit numbers can be generated.

5 0

3 years ago

Not all visitors to a certain company's website are customers. In fact, the website administrator estimates that about 5% of all

Gnom [1K]

Answer:

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

Step-by-step explanation:

For each visitor of the website, there are only two possible outcomes. Either they are looking for the website, or they are not. The probability of a customer being looking for the website is independent of other customers. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5% of all visitors to the website are looking for other websites.

So 100 - 5 = 95% are looking for the website, which means that $p = 0.95$

Find the probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

This is P(X = 2) when n = 4. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = x) = C_{4,2}.(0.95)^{2}.(0.05)^{2} = 0.0135$

0.0135 = 1.35% probability that, in a random sample of 4 visitors to the website, exactly 2 actually are looking for the website.

5 0

3 years ago

Can one of y’all help me with this pls

jolli1 [7]

Answer: A 15

Step-by-step explanation:

5 0

3 years ago

A cube number is rolled 20 times and lands on 1 two times and on 5 four times. Find each experimental probability. Then compare

kykrilka [37]

The experiment probabilities are listed below:

One: 2 out of 20 = 2 / 20 = 0.1 or 10%

Four: 5 out of 20 = 5 / 20 = 1 / 4 = 0.25 = 25%

The theoretical probability of any single number is 1 out of 6 or about 17%.

The experimental probability for ones was less than and for fours it was greater than the theoretical probability.

4 0

4 years ago