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2 years ago

A box measures 2 cm x 0.09 m x 20 mm. what is its volume in cubic centimeters?

1 answer:

4 0

The volume would be 3.6cm4th power because 2cm x 0.09m x 20mm, you have to combine multiplication rules so you have to multiply the 2 x 0.0.09 x 20 and you would get 3.6cmxMxMxM, then you have to add the exponent if the term doesn't have one so it would be 3.6cm1 x m1 x m1 x m1. when you gather it, the sum would be 3.6cmxM1+1+1+1. the total answer would be 3.6cm4th power.

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Simplify 6 - (-2) - 3(-5).<br> -11<br> -7<br> 19<br> 23

Sergeeva-Olga [200]

6 - (-2) - 3(-5) = (6 + 2) + 15 = 8 + 15 = 23

Your answer is D. the last one :)

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No. Angle 1 is an obtuse angle while angle 2 is an acute angle. obtuse angles are more than 90 degrees, which is more than an acute angle's less than 90 degrees.

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(4x-5)^3 - (x^2 + 4x+1)(4x-3)=?

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3 years ago

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Maru [420]

It is d i would include a visual picture but i’m lazy lol

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2 years ago

Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to

hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

$A = \pi r^{2}$

so for choice (A) area is given as $4.375 \times 10^{7}$ . So plug this in A place in formula and then solve for radius r

$4.375 \times 10^{7} = \pi r^{2}$

$\frac{4.375 \times 10^{7}}{\pi} = \frac{\pi r^{2}}{\pi}$

$1.393 \times 10^{7} } = r^{2}$

$\sqrt{1.393 \times 10^{7}} = \sqrt{r^{2}}$

3731.76 = r

So screw A will have
$diameter = 2 \times r = 2 \times 3731.76 = 7463.52$ inches

Similarly for choice (E) area is $1.428 \times 10^{1} = 14.28$
so again plug in formula

$A = \pi r^{2}$

$14.28 = \pi r^{2}$

$\frac{14.28}{\pi} = \frac{\pi r^{2}}{\pi}$

$4.5477 = r^{2}$

$\sqrt{4.5477} = \sqrt{r^{2}}$

2.13201 = r

So screw E will have
$diameter = 2 \times r = 2 \times 2.13201 = 4.26402$ inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: $1\frac{7}{8} = \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875$ inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer

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