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3 years ago

What is the circumference of earth's equator?

Mathematics

1 answer:

AlekseyPX3 years ago

3 0

Answer:

40,075 kilometers

Step-by-step explanation:

The distance around the Earth at the Equator, its circumference, is 40,075 kilometers

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The circumference of a circle is

pantera1 [17]

Answer:

Step-by-step explanation:

the formula for circumference of a circle is 2 x pi x r(radius).

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3 years ago

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In a sale there is 25% off all prices. A chair costs Â£45 in the sale. How much was it before the sale?

garri49 [273]

Answer:

60 pounds

Step-by-step explanation:

Let the normal price be p. The "25%-off" sale price is then 0.75p, and this 0.75p equals 45 pounds. Dividing both sides by 0.75 results in p = 60 pounds.

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3 years ago

50 POINTS

ikadub [295]

You would have to do 6x2= 12 so it’s 12 outcomes

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3 years ago

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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th

creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

$C=A+B=(a_1+b_1,a_2+b_2)$

And its magnitude is:

$C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9$

Where

$a_1=Asinx$

$a_2=Acosx$

$b_1=Bsin(x+90)$

$b_2=Bcos(x+90)$

Using the properties of the sum of two angles in the sin and cosine:

$b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx$

$b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx$

Sustituying in the magnitud of the sum

$C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9$

$C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9$

$C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}$

$C=\sqrt{A^2+B^2} =9$

Solving for B

$A^2+B^2 =9^2$

$B^2 =9^2-A^2$

Sustituying the value of the magnitud of A

$B^2=81-5^2=81-25=56$

$B= 7. 4833$

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3 years ago

What is another way to write 8 2/4

ZanzabumX [31]

Another answer is 34/4

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3 years ago

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