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3 years ago

5

In a student government election, 6 seniors, 2 juniors, and 3 sophomores are running for election. Students elect four at-large

senators. In how many ways can this be done?

2 answers:

Dmitrij [34]3 years ago

5 0

Answer:

330 ways.

Step-by-step explanation:

4 senators of 11 people should be selected, that is a combination of the C(n,r) form, where

n = 11

r = 4

That's C(11,4)

The combinations form uses factorial numbers. This is the formula:

$C(n,r)=\frac{n!}{(n-r)! r!}$

Substituting the variables for their respective data, we have

$C(11,4)=\frac{11!}{(11-4)! 4!}$

$C(11,4)=\frac{11.10.9.8.7!}{7! 4!}$

$C(11,4)=\frac{11.10.9.8}{4!}$

$C(11,4)=\frac{11.10.9.8}{4.3.2}$

$C(11,4)=\frac{7920}{24}$

$C(11,4)=330$

Students can elect four at-large senators of 330 ways.

Hope this helps!

Harrizon [31]3 years ago

3 0

4-0-0
2-1-1
1-2-1
1-0-3
0-1-3

Those are just the ones I can think of so about 5 ways

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Answer:

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Step-by-step explanation:

Sea el punto debajo del puente el punto de referencia y que ambas lanchas se desplazan a velocidad a continuación, las ecuaciones cinemáticas para cada embarcación son presentadas a continuación:

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Donde:

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$x_{A}$ , $x_{B}$ - Posición final de cada embarcación, medido en metros.

$v_{A}$ , $v_{B}$ - Velocidad de cada embarcación, medida en metros por segundo.

$t$ - Tiempo, medido en segundos.

Para determinar la posición en la que ambas embarcaciones se encuentran, se debe determinar el instante en que ocurre a partir de la siguiente condición: $x_{A} = x_{B}$

Igualando (Ec. 1) y (Ec. 2) se tiene que:

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$t = \frac{3\cdot \left(10\,\frac{m}{s} \right)}{10\,\frac{m}{s}-7\,\frac{m}{s}}$

$t = 10\,s$

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$x_{A} = 0\,m + \left(7\,\frac{m}{s} \right)\cdot (10\,s)$

$x_{A} = 70\,m$

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sertanlavr [38]

Hi,

The equation looks like this...

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