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Trava [24]
3 years ago
14

If you would like to improve a populations overall quality of life, the blank career cluster might be best for you

SAT
1 answer:
solmaris [256]3 years ago
5 0
The job you love the most
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B(n)=2^n A binary code word of length n is a string of 0's and 1's with n digits. For example, 1001 is a binary code word of len
Citrus2011 [14]

Answer:

The additional words is 2^n

Explanation:

Given

B(n) = 2^n

Required

Determine the additional words; i.e. B(n + 1) - B(n)

From the given parameters, we have that;

B is a function of n

Such that;

B(n) = 2^n

To calculate B(n+1), we simply substitute n + 1 for n

B(n) = 2^n

B(n + 1) = 2^{n + 1}

Applying laws of indices

B(n + 1) = 2^{n} * 2^1

B(n + 1) = 2^{n} * 2

B(n + 1) = 2(2^{n})

Calculating Additional Binary Code;

B(n + 1) - B(n)

Substitute values for B(n + 1) and B(n)

B(n + 1) - B(n) = 2(2^n) - 2^n

Express 2^n as 2^ n * 1

B(n + 1) - B(n) = 2(2^n) - 2^n * 1

Express 1 as 2^0

B(n + 1) - B(n) = 2(2^n) - 2^n * 2^0

Factorize

B(n + 1) - B(n) = 2^n(2 - 2^0)

B(n + 1) - B(n) = 2^n(2 - 1)

B(n + 1) - B(n) = 2^n(1)

B(n + 1) - B(n) = 2^n

Hence, the additional words is 2^n

8 0
3 years ago
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