Ask question

Ask question

All categories

2 years ago

14

There are 3 inches of snow on the ground when it begins to snow 0.5 inches per hour. Which linear equation represents the total

depth of the snow, in inches, after x hours?

1 answer:

Liono4ka [1.6K]2 years ago

4 0

Well you could write it like this I'm pretty sure:

3 + .5 (x)= In.

You might be interested in

An airplane climbs at an angle of 16° with the ground. Find the ground

Tatiana [17]

Answer:

2403.2

Step-by-step explanation:

We get the length of the hypotenuse, and the base angle. To find the length of the base, we use the cosine of 16° since it is equal to the adjacent side length/ hypotenuse side length or cos 16°= x/2500. The isolate x by multiplying both sides by 2500. The cos 16° is around 0.96126, multiplied by 2500 (cos 16°(2500)) = 2403.1

6 0

2 years ago

96 divided by 6 distributive property of multuiplication

ololo11 [35]

Do 96 divided by 6.

6 goes into 96 16 times. therefore, your answer is 16

6 0

2 years ago

What are the solutions of -1 ≤ x – 3 < 4

cricket20 [7]

Answer:

2 ≤ x < 7

Step-by-step explanation:

-1 ≤ x – 3 < 4

Add 3 to each side

-1+3 ≤ x – 3+3 < 4+3

2 ≤ x < 7

7 0

3 years ago

Jane bought four books 3 cups and seven rings. She paid four dollars per book 5 dollars per cup and $10 Paris. Estimate her chan

Pavlova-9 [17]

4 x4 +5 x 3=31== estimate 30$

3 0

2 years ago

Find the parametric equations for the line that is tangent to the given curve at the given parameter (3cost)i (t^4 -3sint)j

ale4655 [162]

Answer:

Following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

In the given equation, when the point t=0

So,

$\to r(0) = (3 \cos 0)i + (0^4 - 6 \sin 0)j + (2e^{3\times 0})k)$

$= (3 \times 1)i + (0 - 0)j + (2e^{0})k)\\\\ = 3i + 0j + (2 \times 1)k)\\\\ = 3i + 0j + 2k \\$

The value of the coordinates are $3, 0, 2$ . so, the equation of the line is:

$\to \frac{(x-3)}{3 \cos \ t} = \frac{(y-0)}{(t^{4}-6 \sin \ t)} = \frac{(z-2)}{2e^{3t}}=k$

5 0

3 years ago