Which is greater. -7/12 or -5/9

gulaghasi [49]

(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.

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(b) The following functions are positive in quadrant III:

tangent, cotangent

The following functions are negative in quadrant III

cosine, sine, secant, cosecant

A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.

5 0

2 years ago

Given the following triangle, if a = 2 and b = 3, find c. √5 √10 √13

Tems11 [23]

We can use pythagorean theorem:

a^2 + b^2 = c^2

4 + 9 = c^2

13 = c^2

sqrt of 13 = c

Hope this helps!

4 0

2 years ago

Read 2 more answers

Janine has 86 hockey cards in one book and 105 hockey cards in another book. The hockey cards come in packages of 5 cards. If Ja

wel

Answer:

ur pfp... pls get help NOWWW

Step-by-step explanation:

pls stop this madness

8 0

1 year ago

Which exponential function goes through the points (1, 8) and (4, 64)?

Mama L [17]

An exponential function can be expressed as:

y=ab^x we have two points so we can solve

64/8=(ab^4)/(ab^1)

8=b^3

2=b, now we have:

y=a(2^x), using point (4,64)

64=a(2^4)

64=16a

4=a so

y=4(2^x)

6 0

2 years ago

Determine whether each equation below does or does not represent a proportional relationship. support your answer using either a

Triss [41]

Answer:

As the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship.
As the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship.

Step-by-step explanation:

Solving equation A: y = x 

Let us consider the given equation A:

y = x

Putting x = 1 in y = x

y = x

y = 1 ∵ x = 1

Hence, (1, 1) is the ordered pair of y = x

Putting x = 2 in y = x

y = x

y = 2 ∵ x = 2

Hence, (2, 2) is the ordered pair of y = x

Putting x = 3 in y = x

y = x

y = 3 ∵ x = 3

Hence, (3, 3) is the ordered pair of y = x

Putting x = 4 in y = x

y = x

y = 4 ∵ x = 4

Hence, (4, 4) is the ordered pair of y = x

Putting x = 5 in y = x

y = x

y = 5 ∵ x = 5

Hence, (5, 5) is the ordered pair of y = x

Lets us consider all the ordered pairs i.e. (1, 1), (2, 2), (3, 3), (4, 4) and (5, 5) to make a table for y = x.

y x

1 1

2 2

3 3

4 4

5 5

As from the table, lets take the ratio of every point i.e. y/x

For (1, 1), the ratio will be y/x ⇒ 1/1 = 1
For (2, 2), the ratio will be y/x ⇒ 2/2 = 1
For (3, 3), the ratio will be y/x ⇒ 3/3 = 1
For (4, 4), the ratio will be y/x ⇒ 4/4 = 1
For (5, 5), the ratio will be y/x ⇒ 5/5 = 1

Hence, the ratio for all the points on the equation y = x is same. Hence, the equation y = x REPRESENTS a proportional relationship. Please also check the graph in attached figure a.

Solving equation A: y = x +2

Let us consider the given equation A:

y = x + 2

Putting x = 1 in y = x + 2

y = x + 2

y = 1 + 2 ⇒ 3 ∵ x = 1

Hence, (1, 3) is the ordered pair of y = x + 2

Putting x = 2 in y = x + 2

y = x + 2

y = 2 +2 ⇒ 4 ∵ x = 2

Hence, (2, 4) is the ordered pair of y = x + 2

Putting x = 3 in y = x + 2

y = x + 2

y = 3 + 2 ⇒ 5 ∵ x = 3

Hence, (3, 5) is the ordered pair of y = x + 2

Putting x = 4 in y = x + 2

y = x + 2

y = 4 + 2 ⇒ 6 ∵ x = 4

Hence, (4, 6) is the ordered pair of y = x + 2

Putting x = 5 in y = x + 2

y = x + 2

y = 5 +2 ⇒ 7 ∵ x = 5

Hence, (5, 7) is the ordered pair of y = x + 2

Lets us consider all the ordered pairs i.e. (1, 3), (2, 4), (3, 5), (4, 6) and (5, 7) to make a table for y = x + 2.

y x + 2

1 3

2 4

3 5

4 6

5 7

As from the table, lets take the ratio of every point i.e. y/x

For (1, 3), the ratio will be y/x ⇒ 3/1 = 3
For (2, 4), the ratio will be y/x ⇒ 4/2 = 2
For (3, 5), the ratio will be y/x ⇒ 5/3 = 5/3
For (4, 6), the ratio will be y/x ⇒ 6/4 = 3/2
For (5, 7), the ratio will be y/x ⇒ 7/5 = 7/5

Hence, the ratio for all the points on the equation y = x+2 is not same. Hence, the equation y = x + 2 DOES NOT REPRESENT a proportional relationship. Please also check the graph in attached figure a.

Keywords: equation, graph

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6 0

2 years ago