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3 years ago

Jada received a gift of $180. In the first week, she spent a third of the gift money. She continues spending a

Mathematics

1 answer:

Sloan [31]3 years ago

7 0

Answer:

180 minus 60 equals 120

Step-by-step explanation:

1/3 of 180 equals 60 so you would take 60 out of 180 to get 120 and 120 would be the amount that she spent the rest of the weeks

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The equation of the line of best fit is y=3x+2. x=the number of ice cream sales and y= the number of days. Answer the following

Nina [5.8K]

Answer:

all I know is how to get y but y=122

Step-by-step explanation:

y=3(40)+2

y=120+2

y=122

sorry but I dont know what to do for x

3 0

2 years ago

<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20-22x%3D10%5C%5C" id="TexFormula1" title="x^{2} -22x=10\\" alt="x^{2} -22x=10\\"

Ronch [10]

Answer:

Step-by-step explanation:

x^2 - 22x = 10

Next step is to complete the square on the left hand side of the equation and it would be balanced by adding the same number to the right side of the equation. It becomes

x^2 - 22x + (22/2)^2 = 10 + (22/2)^2

x^2 - 22x + (11)^2 = 10 + (11)^2

x^2 - 22x + (11)^2 = 10 + 121

x^2 - 22x + (11)^2 = 131

x^2 - 22x + 121^2 = 131

(x - 11)^2 = 131

Taking square root of both the left hand side and the right hand side of the equation, it becomes

x - 11 = ±√131

x - 11 = ±11.45

Adding 11 to the left hand side and the right hand side of the equation, it becomes

x - 11 + 11 = ±11.45 + 11

x = 11.45 + 11 or x = -11.45 + 11

x = 22.45 or x = - 0.45

5 0

3 years ago

If 2p + p = 20 then what is 2p - 5 =

Wewaii [24]

Ok first we have to find out whats 2p+p=20 combine like terms to get 3p=20 the divide 3 on each side to get p=6 2/3 then we plug in 6 2/3 to 2p-5 so 2(6 2/3) -5 so its 12.666-5 to get 7.666 so that's the answer.

4 0

3 years ago

A ball is thrown into the air by a baby alien on a planet in the system of Alpha Centauri with a velocity of 30 ft/s. Its height

Crank

Answer:

a) h = 0.1: $\bar v = -11\,\frac{ft}{s}$ , h = 0.01: $\bar v = -10.1\,\frac{ft}{s}$ , h = 0.001: $\bar v = -10\,\frac{ft}{s}$ , b) The instantaneous velocity of the ball when $t = 2\,s$ is $-10$ feet per second.

Step-by-step explanation:

a) We know that $y = 30\cdot t -10\cdot t^{2}$ describes the position of the ball, measured in feet, in time, measured in seconds, and the average velocity ( $\bar v$ ), measured in feet per second, can be done by means of the following definition:

$\bar v = \frac{y(2+h)-y(2)}{h}$

Where:

$y(2)$ - Position of the ball evaluated at $t = 2\,s$ , measured in feet.

$y(2+h)$ - Position of the ball evaluated at $t =(2+h)\,s$ , measured in feet.

$h$ - Change interval, measured in seconds.

Now, we obtained different average velocities by means of different change intervals:

$h = 0.1\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.1) = 30\cdot (2.1)-10\cdot (2.1)^{2}$

$y(2.1) = 18.9\,ft$

$\bar v = \frac{18.9\,ft-20\,ft}{0.1\,s}$

$\bar v = -11\,\frac{ft}{s}$

$h = 0.01\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.01) = 30\cdot (2.01)-10\cdot (2.01)^{2}$

$y(2.01) = 19.899\,ft$

$\bar v = \frac{19.899\,ft-20\,ft}{0.01\,s}$

$\bar v = -10.1\,\frac{ft}{s}$

$h = 0.001\,s$

$y(2) = 30\cdot (2) - 10\cdot (2)^{2}$

$y (2) = 20\,ft$

$y(2.001) = 30\cdot (2.001)-10\cdot (2.001)^{2}$

$y(2.001) = 19.99\,ft$

$\bar v = \frac{19.99\,ft-20\,ft}{0.001\,s}$

$\bar v = -10\,\frac{ft}{s}$

b) The instantaneous velocity when $t = 2\,s$ can be obtained by using the following limit:

$v(t) = \lim_{h \to 0} \frac{x(t+h)-x(t)}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot (t+h)-10\cdot (t+h)^{2}-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot t +30\cdot h -10\cdot (t^{2}+2\cdot t\cdot h +h^{2})-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot t +30\cdot h-10\cdot t^{2}-20\cdot t \cdot h-10\cdot h^{2}-30\cdot t +10\cdot t^{2}}{h}$

$v(t) = \lim_{h \to 0} \frac{30\cdot h-20\cdot t\cdot h-10\cdot h^{2}}{h}$

$v(t) = \lim_{h \to 0} 30-20\cdot t-10\cdot h$

$v(t) = 30\cdot \lim_{h \to 0} 1 - 20\cdot t \cdot \lim_{h \to 0} 1 - 10\cdot \lim_{h \to 0} h$

$v(t) = 30-20\cdot t$

And we finally evaluate the instantaneous velocity at $t = 2\,s$ :

$v(2) = 30-20\cdot (2)$

$v(2) = -10\,\frac{ft}{s}$

The instantaneous velocity of the ball when $t = 2\,s$ is $-10$ feet per second.

8 0

3 years ago

KM and NP are parallel lines. Which angles are corresponding angles?

Charra [1.4K]

Answer:

nol and klj

Step-by-step explanation:

since they are parallel lines you would look for which angles correspond to the sample place on the intersection

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3 years ago