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Rainbow [258]
3 years ago
14

Factor p 2 - 2p - 24. (p - 3)(p + 8) (p + 6)(p - 4) (p - 6)(p + 4)

Mathematics
2 answers:
puteri [66]3 years ago
6 0
P^2-2p-24
p^2-6p+4p-24
p(p-6) +4(p-6)
(p+4)(p-6) is answer D
Zepler [3.9K]3 years ago
4 0

Answer:  The correct option is (C) (p-6)(p+4).

Step-by-step explanation:  We are given to factor the following quadratic expression :

E=p^2-2p-24~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

To factor the given expression, we need two integers with sum -2 and product -24. Those two integers are -6 and 4.

The factorization of expression (i) is as follows :

E\\\\=p^2-2p-24\\\\=p^2-6p+4p-24\\\\=p(p-6)+4(p-6)\\\\=(p-6)(p+4).

Thus, the required factored form of the given expression is (p-6)(p+4).

Option (C) is CORRECT.

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Lin uses an app to graph the charge on her phone.
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Answer:

  • See below

Step-by-step explanation:

<u>Use the graph to answer the following questions:</u>

When did she start using her phone?

  • At 2 afternoon

When did she start charging her phone?

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While she was using her phone, at what rate was Lin’s phone battery dying?

<u>From 100% to 40% between 2PM and 4 PM:</u>

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8 0
2 years ago
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-3f - 10

Step-by-step explanation:

-1 times 10 = -10

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4 0
3 years ago
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Which is bigger -6 1/3 or -6.375
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5 0
3 years ago
Last Sunday a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the stor
Marat540 [252]

Answer:

D. \frac{400p}{500-p}

Step-by-step explanation:

let's call A the number of copies sold of newspaper A and B the number of copies sold of newspaper B.

So, we can formulate the following equations from the sentence: a certain store sold copies of 256 Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each as:

A + B = 256                               (1)

1A + 1.25 B = Total Revenue    (2)

Then, r and p are equal to:

r=\frac{A}{Total Revenue}*100=\frac{100A}{A+1.25B}     (3)

p=\frac{A}{256} *100=\frac{100A}{256}                            (4)

Isolating A from (4) and B from (1), we get:

A=\frac{256p}{100} =2.56p                (5)

B=256-A=256-2.56p                         (6)

Finally, replacing (5) and (6) in (3), we get:

r=\frac{100A}{A+1.25B}=\frac{100(2.56p)}{2.56p+1.25(256-2.56p)}\\\\r=\frac{256p}{2.56p+320-3.2p}=\frac{256p}{320-0.64p}\\\\r=\frac{256p/0.64}{(320-0.64p)/0.64}=\frac{400p}{500-p}

7 0
4 years ago
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