T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
Answer:
C Both the mean and median are appropriate measures of center.
Step-by-step explanation:
Answer:
that means you need to find the surface area, but not the part that is touching the ground or the bottom.
Let us suppose the width is x feet
the length is given 12 feet
Perimeter of teh garden = 2( Length + width )= 2( 12+ x)
Fencing required = perimeter of garden
36 = 2( 12+x)
36 = 2*12 + 2x
36 = 24 + 2x
36-24 = 2x
12 = 2x
12/2 = x
6 = x
Width = x feet = 6 feet .Answer .
