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castortr0y [4]
3 years ago
10

Simplify the expression 83 + 263 + 17 - 63.

Mathematics
2 answers:
lys-0071 [83]3 years ago
8 0
Hello,

The answer is: "346+-46="

Reason:

263+83=346

17-63=-46

346+-46

If you need anymore help feel free to ask me!

Hope this helps!

~Nonportirt
9966 [12]3 years ago
5 0
The final answer is 300
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Find the difference between the product of 2.5 and 7.5 and the sum of2.75 and 9.55​
Brums [2.3K]

Answer:

6.45

Step-by-step explanation:

The answer=2.5*7.5-(2.75+9.55)=18.75-(12.3)=6.45

8 0
2 years ago
Find the value of w-9 given that –3w+5 = 2
melamori03 [73]

Answer:

-8

Step-by-step explanation:

Solving for w given the equation, -3w +5 = 2:

-3w +5 = 2 \\ -3w +5 -5 = 2 -5 \\ -3w = -3 \\ \frac{-3w}{-3} = \frac{-3}{-3} \\ w = 1

Solving for w -9 when w = 1

1 -9 \\ -8

3 0
2 years ago
In the figure above, the vertices of square
Olin [163]

(C) 6 + 3√3

<u>Explanation:</u>

Area of the square = 3

a X a = 3

a² = 3

a = √3

Therefore, QR, RS, SP, PQ = √3

ΔBAC ≅ ΔBQR

Therefore,

\frac{BQ}{BA} = \frac{QR}{AC}

\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

BQ = √3

So, BQ, QR, BR = √3 (equilateral triangle)

Let AP and SC be a

So, AQ and RC will be 2a

In ΔAPQ,

(AP)² + (QP)² = (AQ)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

So, AP and SC = 1

and AQ and RC = 2 X 1 = 2

Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR

Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3

Perimeter = 6 + 3√3

Therefore, the perimeter of the triangle is 6 + 3√3

8 0
3 years ago
Consider the end behavior of the function g(x) = 4|x − 2| − 3.
horrorfan [7]

Answer:

Positive ; Positive

Step-by-step explanation:

Since there's a modulus, negative values also become positive

3 0
3 years ago
Read 2 more answers
Write a rule for the nth term of the arithmetic sequence described below.
belka [17]

Answer:

an = 115 + (n - 1) (-6)

a25 = - 29

Step-by-step explanation:

We use the definition for the nth term of an arithmetic sequence:

an = a1 + (n - 1) d

a5 = 91 = a1 + (5 - 1) d

91 = a1 + 4 d

a20 = 1 = a1 + (20 - 1) d = a1 + 19 d

1 = a1 + 19 d

now we subtract term by term one expression from the other

90 = 4 d - 19 d

90 = - 15 d

divide both sides by -15 to isolate d

d = 90 / (-15) = -6

Now we can calculate what a1 is using for example:

1 = a1 + 19 d

1 = a1 - 114

add 114 to both sides:

115 = a1

Then our general expression for the sequence is:

an = 115 + (n - 1) (-6)

We can now use it to calculate the value of a25:

a25 = 115 + (24) * (-6) = -29

7 0
2 years ago
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