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olga2289 [7]
3 years ago
12

I need help with this assignment

Mathematics
1 answer:
Slav-nsk [51]3 years ago
4 0

Answer and Step-by-step explanation:

This is negative slope (or a downwards negative slope).

When the slope is negative, the line goes from right to left from top to bottom.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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The length of a box is 4 inches longer than its width, and the height is 2 inches shorter than the width. which equation can you
andreev551 [17]
L=w+4 this shows the length is 4 inches longer than width
h=w-2 this shows the height is 2 inches shorter than the width
volume=lwh
so 240=lwh=(w+4)(w)(w-2)
simplify and solve to find the width then you can use that to find the other values as well.
3 0
3 years ago
— 2y – Зу +8 = 8 — 5у – 12
jasenka [17]

Answer:

No Solution.

Step-by-step explanation:

Equality equation:

— 2y – Зу +8 = 8 — 5у – 12  (Given)

-5y + 8 = -4 - 5y (distributive property of equality)

-5y = -12 - 5y (subtraction property of equality)

= -12 (addition property of equality)

when you add 5y on both sides it cancels the 5y out, it's no solution.

<em><u>Ace-The Kid Laroi</u></em>

6 0
3 years ago
Let X be the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. The article "Methodo
Shkiper50 [21]

Answer:

a) P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.6288

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.1954=0.4335

b) P(4\leq X\leq 8)=0.1954+0.1563+0.1042+0.0595+0.0298=0.5452

c) P(X \geq 8) = 1-P(X

d) P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

Step-by-step explanation:

Let X the random variable that represent the number of material anomalies occurring in a particular region of an aircraft gas-turbine disk. We know that X \sim Poisson(\lambda=4)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda=4  , Var(X)=\lambda=2, Sd(X)=2

a. Compute both P(X≤4) and P(X<4).

P(X\leq 4)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)+P(X=4)

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-4} 4^0}{0!}=e^{-4}=0.0183

P(X=1)=\frac{e^{-4} 4^1}{1!}=0.0733

P(X=2)=\frac{e^{-4} 4^2}{2!}=0.1465

P(X=3)=\frac{e^{-4} 4^3}{3!}=0.1954

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X\leq 4)=0.0183+0.0733+ 0.1465+0.1954+0.1954=0.9646

P(X< 4)=P(X\leq 3)=P(X=0)+P(X=1)+ P(X=2)+P(X=3)

P(X< 4)=P(X\leq 3)=0.0183+0.0733+ 0.1465+0.5311=0.7692

b. Compute P(4≤X≤ 8).

P(4\leq X\leq 8)=P(X=4)+P(X=5)+ P(X=6)+P(X=7)+P(X=8)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(X=7)=\frac{e^{-4} 4^7}{7!}=0.0595

P(X=8)=\frac{e^{-4} 4^8}{8!}=0.0298

P(4\leq X\leq 8)=0.1954+0.1563+ 0.1042+0.0595+0.0298=0.5452

c. Compute P(8≤ X).

P(X \geq 8) = 1-P(X

P(X \geq 8) = 1-P(X

d. What is the probability that the number of anomalies exceeds its mean value by no more than one standard deviation?

The mean is 4 and the deviation is 2, so we want this probability

P(4\leq X \leq 6)=P(X=4)+P(X=5)+P(X=6)

P(X=4)=\frac{e^{-4} 4^4}{4!}=0.1954

P(X=5)=\frac{e^{-4} 4^5}{5!}=0.1563

P(X=6)=\frac{e^{-4} 4^6}{6!}=0.1042

P(4\leq X \leq 6)=0.1954+0.1563+0.1042=0.4559

4 0
3 years ago
It’s asking for the area<br> Please help! Thank you!
Eddi Din [679]

Answer: x^2+9x+20

Step-by-step explanation:

To find the area you multiply the sides so it should be (x+4)(x+5) which is x^2+9x+20. Good luck!

6 0
3 years ago
Two trains are traveling at a constant rate. Which train has the greater speed?
aniked [119]

AnswerAccording to my caculations its B

Step-by-step explanation:Just trust me

4 0
3 years ago
Read 2 more answers
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