I think the answer is option c.one
there is only one sign change in the whole equation so possiblythe answe must be one. correct me if i am wrong
-6m+19
1/2(-12m+38)
All we have to do is simply distribute the 1/2.
1/2(-12m) + 1/2(38)
(-6m) + 19
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Answer:
it's -1 to 1.
Step-by-step explanation:
after solving
we get ![\frac{125x^{27}}{8y^{39}}](https://tex.z-dn.net/?f=%5Cfrac%7B125x%5E%7B27%7D%7D%7B8y%5E%7B39%7D%7D)
Step-by-step explanation:
We need to simplify the expression:
![\left(\frac{\left2x^{-7}y^7\right}{5x^2y^{-6}}\right)^{-3}](https://tex.z-dn.net/?f=%5Cleft%28%5Cfrac%7B%5Cleft2x%5E%7B-7%7Dy%5E7%5Cright%7D%7B5x%5E2y%5E%7B-6%7D%7D%5Cright%29%5E%7B-3%7D)
Solving
![=\frac{1}{\left(\frac{\left2x^{-7}y^7\right}{5x^2y^{-6}}\right)^{3}}\\\\=\frac{1}{\left(\frac{\left2y^{7+6}\right}{5x^{2+7}}\right)^{3}}\\=\frac{1}{\left(\frac{\left2y^{13}\right}{5x^{9}}\right)^{3}}\\=\frac{1}{\left(\frac{\left2^3y^{13*3}\right}{5^3x^{9*3}}\right)}\\=\frac{1}{\left(\frac{\left8y^{39}\right}{125x^{27}}\right)}\\We\,\,know\,\,\frac{1}{\frac{b}{a}}=\frac{a}{b}\\Applying the rule:\\=\frac{125x^{27}}{8y^{39}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2x%5E%7B-7%7Dy%5E7%5Cright%7D%7B5x%5E2y%5E%7B-6%7D%7D%5Cright%29%5E%7B3%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2y%5E%7B7%2B6%7D%5Cright%7D%7B5x%5E%7B2%2B7%7D%7D%5Cright%29%5E%7B3%7D%7D%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2y%5E%7B13%7D%5Cright%7D%7B5x%5E%7B9%7D%7D%5Cright%29%5E%7B3%7D%7D%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft2%5E3y%5E%7B13%2A3%7D%5Cright%7D%7B5%5E3x%5E%7B9%2A3%7D%7D%5Cright%29%7D%5C%5C%3D%5Cfrac%7B1%7D%7B%5Cleft%28%5Cfrac%7B%5Cleft8y%5E%7B39%7D%5Cright%7D%7B125x%5E%7B27%7D%7D%5Cright%29%7D%5C%5CWe%5C%2C%5C%2Cknow%5C%2C%5C%2C%5Cfrac%7B1%7D%7B%5Cfrac%7Bb%7D%7Ba%7D%7D%3D%5Cfrac%7Ba%7D%7Bb%7D%5C%5CApplying%20the%20rule%3A%5C%5C%3D%5Cfrac%7B125x%5E%7B27%7D%7D%7B8y%5E%7B39%7D%7D)
So, after solving
we get ![\frac{125x^{27}}{8y^{39}}](https://tex.z-dn.net/?f=%5Cfrac%7B125x%5E%7B27%7D%7D%7B8y%5E%7B39%7D%7D)
Keywords: Exponents in fractions
Learn more about Exponents in fractions at:
#learnwithBrainly
Answer:
6 or -1.5
Step-by-step explanation:
We can let this integer be x.
Therefore, according to the question we have:
![2x^2-18=9x](https://tex.z-dn.net/?f=2x%5E2-18%3D9x)
Subtracting 9x, we have a quadratic:
![2x^2-9x-18=0](https://tex.z-dn.net/?f=2x%5E2-9x-18%3D0)
Plugging into the quadratic equation:
![\frac{9+\sqrt{81+144}}{4}, \frac{9-\sqrt{81+144}}{4},](https://tex.z-dn.net/?f=%5Cfrac%7B9%2B%5Csqrt%7B81%2B144%7D%7D%7B4%7D%2C%20%5Cfrac%7B9-%5Csqrt%7B81%2B144%7D%7D%7B4%7D%2C)
the square root of 81+144 is 15, so the answer is either 6 or -1.5