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3 years ago

13

Together, Matthew and Daniel have 67 DVDs. Matthew's collection has 3 times as many DVDs as Daniel's collection. Write an algebr

aic equation can be used to determine the number of DVDs in Daniel's collection. Use x as your variable.

1 answer:

ryzh [129]3 years ago

8 0

<h3>Answer: 3x + x = 67</h3><h3>To solve: 4x = 67</h3><h3> /4. /4</h3><h3>x = 16.75</h3><h3></h3>

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Pani-rosa [81]

Answer:

29.87

Step-by-step explanation:

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3 years ago

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maks197457 [2]

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3 years ago

What is the difference between a tax credit and a tax deduction?

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4 years ago

A department store buys 100 shirts at a cost of $2 comma 700 and sells them at a selling price of $30 each. Find the percent m

Zinaida [17]

The percent markup is 11.11 %

<em><u>Solution:</u></em>

Given that, the store buys 100 shirts at a cost of $ 2700

Let us find the cost of 1 shirt

$\text{cost of 1 shirt } = \frac{2700}{100} = 27$

The store sells them at $ 30 each

Therefore,

Cost price of 1 shirt = $ 27

Selling price of 1 shirt = $ 30

Markup price = Selling price - Cost price

Markup price = 30 - 27

Markup price = 3

Thus markup price is $ 3

<em><u>The percent markup is given as:</u></em>

$\text{Percent markup } = \dfrac{\text{Mark up}}{\text{Cost price}}\times100\\\\\text{Percent markup } = \frac{3}{27} \times 100\\\\\text{Percent markup } = 11.11$

Thus the percent markup is 11.11 %

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4 years ago

Pls help only if yk it ill give brainliest to the correct answer !

IgorC [24]

Answer:

$x=-0.3$

$x=-11.7$

Step-by-step explanation:

$4x^2+24x+13=2x^2+6\\\mathrm{Subtract\:}6\mathrm{\:from\:both\:sides}\\4x^2+24x+13-6=2x^2+6-6\\Simplify\\4x^2+24x+7=2x^2\\\mathrm{Subtract\:}2x^2\mathrm{\:from\:both\:sides}\\4x^2+24x+7-2x^2=2x^2-2x^2\\Simplify\\2x^2+24x+7=0\\\mathrm{Solve\:with\:the\:quadratic\:formula}\\Quadratic\:Equation\:Formula\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=24,\:c=7:\quad x_{1,\:2}=\frac{-24\pm \sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}\\x=\frac{-24+\sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}:\quad \frac{-12+\sqrt{130}}{2}\\x=\frac{-24-\sqrt{24^2-4\cdot \:2\cdot \:7}}{2\cdot \:2}:\quad -\frac{12+\sqrt{130}}{2}\\The\:solutions\:to\:the\:quadratic\:equation\:are:\\x=\frac{-12+\sqrt{130}}{2},\:x=-\frac{12+\sqrt{130}}{2}\\\\quad x=-0.29912\ ,\:x=-11.70087$

6 0

3 years ago