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Troyanec [42]
2 years ago
11

Which of the following is the correct factorization of the polynomial below 2x^2-12x+18

Mathematics
2 answers:
balandron [24]2 years ago
7 0

Answer:

\large\boxed{2x^2-12x+18=2(x-3)(x-3)=2(x-3)^2}

Step-by-step explanation:

2x^2-12x+18=(2)(x^2)-(2)(6x)+(2)(9)\\\\=(2)(x^2-6x+9)=2(x^2-2(x)(3)+3^2)\\\\\text{use}\ (a+b)^2=a^2+2ab+b^2\\\\=2(x-3)^2=2(x-3)(x-3)

Talja [164]2 years ago
4 0

Answer:

It can be written as 2(x-3)(x-3)  or 2(x-3)².

Step-by-step explanation:

2x² - 12x + 18 = 2(x² - 6x +9) = 2(x-3)(x-3)  =2(x-3)²

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Answer:

The equation in the standard form is

y+2x=5

Step-by-step explanation:

Given the points

  • (6, -7)
  • (4, -3)

Finding the slope between (6, -7) and (4, -3)

\left(x_1,\:y_1\right)=\left(6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(4,\:-3\right)

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As the point-slope form is defined as

y-y_1=m\left(x-x_1\right)

substituting the values m = -2 and the point (6, -7)

y-y_1=m\left(x-x_1\right)

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Writing the equation in the standard form form

As we know that the equation in the standard form is

Ax+By=C

where x and y are variables and A, B and C are constants

converting the equation in standard form

y-\left(-7\right)=-2\left(x-6\right)

y+7=-2\left(x-6\right)

subtract 7 from both sides

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Therefore, the equation in the standard form is

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