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marta [7]
3 years ago
10

Which property is illustrated by the following statement statement

Mathematics
2 answers:
Veronika [31]3 years ago
7 0

Answer:symmetric

Step-by-step explanation: a p e x

Zigmanuir [339]3 years ago
6 0

Answer:

C) Symmetric

Step-by-step explanation:

The symmetric property is the idea that if A = B, then B = A. Flipping the equation around doesn't matter.

It's like saying 2+3 = 5 is the same as 5 = 2+3. We can extend the symmetric property to not only deal with equations, but include congruence statements as well.

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Answer:

im pretty sure its the 3rd one

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3 years ago
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Which exspression is equivalent to :
dlinn [17]

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C

Step-by-step explanation:

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3 years ago
Given log Subscript 3 Baseline 2 almost-equals 0. 631 and log Subscript 3 Baseline 7 almost-equals 1. 771, what is log Subscript
kari74 [83]

You can use the properties of logarithm to get to the solution.

The approximate value for given term is given by

log_3(14) \approx 2.402

<h3>What is logarithm and some of its useful properties?</h3>

When you raise a number with an exponent, there comes a result.

Lets say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using logarithm as follows

b = log_a(c)

Some properties of logarithm are:

log_a(b) = log_a(c) \implies b = c\\\\\log_a(b) + log_a(c) = log_a(b \times c)\\\\log_a(b) - log_a(c) = log_a(\frac{b}{c})

<h3>Using the above properties</h3>

log_3(2) + log_3(7) = log_3(2 \times 7) = log_3(14)\\\\0.631 + 1.771  = log_3(14)\\\\log_3(14) = 2.402

Thus,

The approximate value for given term is given by

log_3(14) \approx 2.402

Learn more about logarithm here:

brainly.com/question/20835449

5 0
2 years ago
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3 0
3 years ago
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K/5+14=13<br> what is the answer and how you got the answer.
abruzzese [7]

Answer:

\frac{k}{5+14} = 13 : k = 247\\

Step-by-step explanation:

\frac{k}{5+14} = 13

Multiply both sides by 19:

\frac{19k}{5+14} = 13 * 19

Simplify:

k = 247

Hope I helped, if so may I get brainliest and a thanks?

Thank you, have a good day! =)

6 0
3 years ago
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