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STALIN [3.7K]
3 years ago
6

In order to estimate the mean amount of time computer users spend on the internet each month, how many computer users must be su

rveyed in order to be 95% confident that your sample mean is within 11 minutes of the population mean? Assume that the standard deviation of the population of monthly time spent on the internet is 202 min. The minimum sample size required is_______computer users. (Round UP to the nearest whole number.)
Mathematics
1 answer:
prisoha [69]3 years ago
6 0

Answer:

1568

Step-by-step explanation:

The computation of the minimum sample size is shown below:

Given that

Error E = 11

The population standard deviation \sigma =217

Confidence level 1-α = 95%

Now following formula should be used

n > (Zalpha ÷ 2 × sigma ÷ E)^2

As we know that

Zalpha ÷ 2= 1.96

Now the sample size is

n> (1.96 × 202  ÷ 10)^2

= 1568

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To solve this, we’ll have to use inverse operations.

Since addition is the inverse to subtraction, we’ll add 20 to 620.

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From there, since division is the inverse of multiplication, we’ll divide .75 by 640.

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Therefore, 853.33 would be your answer! You can check this by solving the equation forwards (853.33 x .75 = ~640, 640 - 20 = 620.)

Hope this helps! :)

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