With each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5.
<h3>What is slope-intercept form?</h3>
The slope-intercept form is just a means of stating a line's equation so that both the slope (steepness) as well as y-intercept (where another line crosses this same vertical y-axis) are obvious. This expression is frequently referred to as y = mx + b.
<h3>According to the given information:</h3>
To begin, are using the slope formula to figure out the average slope between two points here.
Let:
x1 = 4
y1 = -1
x2 = -2
y2 = -1
m = (y2-y1)/(x2-x1)
= (-1 - (-1))/ (4-(-1))
= 0/5
= 0
So the slope is 0.
We must now calculate the y-intercept. This will be accomplished by converting a single of the points and also the slope together into a point-slope linear equation. y2-y1 = m(x2-x1).
Let’s plug in the point (5,0).
So we get y-(-0) = (0/5)(x-(-5)) ⇒ y+0
= (0/5)x + 0 ⇒ y
So,
Y = 0
X = 5
with each line, a slope-intercept relationship (4,-1) and (-2,-1).
Y = 0 ,X = 5
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Hello from MrBillDoesMath!
Answer:
12 m n^2
Discussion:
3m * 4 * n * n = => 3* 4 = 12
12 m * n * n => as n*n = n^2
12 m n^2
Thank you,
MrB
6х=59:3
6х=19,6
Х=19,6:6
Х=3,2
