Option A
Elena need to ride around the loop four or more times
<em><u>Solution:</u></em>
Given that Elena plans to ride her bicycle 5 miles to a park and then ride several times around a loop in the park that is 3 miles long
Then she will ride the same way home
She wants to ride a total of at least 22 miles
<em><u>Given inequality is:</u></em>
3t + 10 > 22
Where "t" is the number of times Elena rides around the loop
<em><u>Solve fot "t" in given inequality</u></em>
3t + 10 > 22
Subtract 10 both sides
3t + 10 - 10 > 22 - 10
3t > 12
Divide by 3 both sides
t > 4
The solution is all real numbers greater than or equal to 4
Which means 4 or more times
Therefore, Option A is correct.
Answer:
Yes, a minimum phase continuous time system is also minimum phase when converted into discrete time system using bilinear transformation.
Step-by-step explanation:
Bilinear Transform:
In digital signal processing, the bilinear transform is used to convert continuous time system into discrete time system representation.
Minimum-Phase:
We know that a system is considered to be minimum phase if the zeros are situated in the left half of the s-plane in continuous time system. In the same way, a system is minimum phase when its zeros are inside the unit circle of z-plane in discrete time system.
The bilinear transform is used to map the left half of the s-plane to the interior of the unit circle in the z-plane preserving the stability and minimum phase property of the system. Therefore, a minimum phase continuous time system is also minimum phase when converted into discrete time system using bilinear transformation.
Coming from a 6th grader but I hope this is right!
Polynomials of degree greater than 2 can have more than one max or min value. The largest possible number of minimum or maximum points is one less than the degree of the polynomial. The following examples illustrate several possibilities.
since the degree is 4
number of possible extreme values = 4 -1 = 3
Answer:
14
Step-by-step explanation:
a=1
b=2
d=2
c=10
K+L = 10¹+2² = 10+4 = 14
Given:
Selling price of a machine = 7000/-
Gross loss = 20%.
To find:
The cost and gross loss.
Solution:
Let x be the cost of machine.
According to the question,
Divide both sides by 0.8.
So, the cost of the machine is 8750/-.
Now,
Therefore, the gross loss is 1750/-.
