Answer:
You just find the volume of the cup and subtract the volume of the froth (whatever that is).
V(cup) = pi * r^2 * h
...........= pi * 4.3^2 * 11.2
...........= 650.586cm^3
V(froth) = pi*r^2*h
............= pi*4.3^2*0.4
.............=23.232cm^3
V(hot chocolate) = V(cup) - V(froth)
.........................= 650.586 - 23.232
.........................= 627cm^3
<span><em>"2 batches of soup will serve 8 people."</em>
<u>Then x </u></span><span><u>batches of soup will serve 120 people
</u>120.2 = 8.x
x = 30 batches of soup will serve 120 people.
<em>"2 onions for 1 batch"</em>
<u>Then y onions for 30 batches
</u>30.2 = 1.y
y = 60 onions<u>
</u></span>
I think the answer would be D.
There is 30 students from each grade so we have 30/120 already then add 12 from 9th grade math and add 10 more from 10th grade math, then add 7 from 12th grade math.
30 + 12 + 10 + 7 = 59
59/120 students.
Answer:
169.5 yd²
Step-by-step explanation:
See attachment.
In situations like this, ALWAYS (!) make as sketch.
Divide the areas by adding dotted lines on sensible places, and write in the missing numbers for the correct distances.
The only possible difficult one is the triangle, which is the half of a rectangle. So you are dealing with a series of areas of rectangles. That is really easy if you understand what you are doing.
Total area =
area 1 + area 2 + area 3 + area 4
10*4 + 4*7 + 3*13 + (0.5 * 7*17)
40 + 28 + 42 + 59.5
Total area = 169.5 yd²
Answer:
Step-by-step explanation:
<u>Given equation:</u>
- x² + y² + 8x - 4y - 7 = 0
<u>Convert this to standard form by completing the square:</u>
- (x - h)² + (y - k)² = r², where (h, k) - center, r - radius
- x² + 2*4x + 4² + y² - 2*2y + 2² - 16 - 4 - 7 = 0
- (x + 4)² + (y - 2)² - 27 = 0
- (x + 4)² + (y - 2)² = 27
- (x + 4)² + (y - 2)² = (√27)²
The center is (- 4, 2) and the radius is √27