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wolverine [178]
3 years ago
9

Two cars start at the same time, but travel in opposite directions. One car's average speed is 20 miles per hour (mph). At the e

nd of 2 hours, the two cars are 120 miles apart. Find the
average speed in mph of the other car. (Enter an exact number.)
help
X mph
Need Help?
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Mathematics
1 answer:
Otrada [13]3 years ago
5 0

Answer:

The first car's speed is 40 mph. 2 hours at that rate equals 80 miles. So:

 

140-80=60

60 miles/2 hours=30 mph as the rate of the second car.

Step-by-step explanation:

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The television show CSI: Shoboygan has been successful for many years. That show recently had a share of 18, meaning that among
jeyben [28]

Answer:

(a) The value of P (None) is 0.062.

(b) The value of P(at least one) is 0.938.

(c) The value of P(at most one) is 0.253.

(d) The event is not unusual.

Step-by-step explanation:

Let <em>X</em> = number of households watching the show.

The probability of the random variable <em>x</em> is, P (X) = <em>p</em> = 0.18.

The sample selected for the survey is of size, <em>n</em> = 14

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 14 and <em>p</em> = 0.18.

The probability of a Binomial distribution is computed using the formula:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,...

(a)

Compute the probability that none of the households are tuned to CSI: Shoboygan as follows:

P(X=0)={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}=1\times1\times0.06214=0.062

Thus, the value of P (None) is 0.062.

(b)

Compute the probability that at least one household is tuned to CSI: Shoboygan as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-0.062\\=0.938

Thus, the value of P(at least one) is 0.938.

(c)

Compute the probability that at most one household is tuned to CSI: Shoboygan as follows:

P (X ≤ 1) = P (X = 0) + P (X = 1)

             ={14\choose 0}(0.18)^{0}(1-0.18)^{14-0}+{14\choose 1}(0.18)^{1}(1-0.18)^{14-1}\\=0.062+0.191\\=0.253

Thus, the value of P(at most one) is 0.253.

(d)

An event that has a very low probability of occurrence is known as an unusual event.

The probability of the event "at most one household is tuned to CSI: Shoboygan" is 0.253.

This probability value is not low.

Hence, the event is not unusual.

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3 years ago
Last season two running back's on the college football team rush for a combined 1550 yards one rushed four times as many yards a
dmitriy555 [2]

Answer:

The player with the most runs had a rush of 1,240 yards

Step-by-step explanation:

In this question, we are asked to calculate the number of yards that was rushed by one of two person given their combined run and an extra information.

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By adding both together, we have a total of 1550 yards

Mathematically, this means that x + 4x = 1550

5x = 1550

x = 1550/5 = 310 rushes

The second player had a rush of 4x and that is 4 * 310 = 1,240 rushes

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3 years ago
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