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weqwewe [10]
3 years ago
9

PLS HELP I WILL MARK YOU BRAINLIEST

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
6 0

Answer:

Part B: Increasing-1,5

           Decreasing -3

           Constant -2,4

Part C: Non linear

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I NEED HELP ASAP!!!! SOLVE THIS IT'S AN IMAGE!!!!
joja [24]

Answer:

y = -7

Step-by-step explanation:

Put x = 2 in any one of the equation

5x +2y = -4

5*2 + 2y = -4

10 +2y = -4

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      2y = -14

        y = -14/2

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6 0
3 years ago
Read 2 more answers
drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This mon
Kisachek [45]

Complete question is:

A large pool of adults earning their first drivers license includes 50% low- risk drivers, 30% moderate-risk drivers, and 20% high-risk drivers. Because these drivers have no prior driving record, an insurance company considers each driver to be randomly selected from the pool. This month, the insurance company writes 4 new policies for adults earning their first drivers license. What is the probability that these 4 will contain at least two more high-risk drivers than low-risk drivers?

Answer:

probability that these 4 will contain at least two more high-risk drivers than low-risk drivers = 0.0488

Step-by-step explanation:

Let H represent High risk

M represent moderate risk

L represent Low risk.

The following combinations will satisfy the condition that there are at least two more high-risk drivers than low-risk drivers: HHHH, HHHL, HHHM, HHMM

The HHHH case has probability 0.2 ⁴ = 0.0016

The HHHL case has probability 4 × 0.2³ × 0.3 = 0.0096 (This is because L can be in four different places)

Similarly, the HHHM case has probability 4 × 0.2 ³ × 0.5 = 0.016

Lastly, the HHMM case has probability 6 × 0.2 ² × 0.3 ² = 0.0216 (This is because the number of ways to choose places for two M letters in this way is 6)

Summing all these probabilities, we have;

0.0016 + 0.0096 + 0.016 + 0.0216 = 0.0488

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2 years ago
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DerKrebs [107]
40% percent times 70 is want I believe
3 0
3 years ago
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Describe the center and spread of the data using either the mean and standard deviation or the five-number summary. Justify your
goblinko [34]

Answer:

The distribution is skewed, so use the five-number summary. range: 38, median: 16, half of the data are between 9.5 and 25

Step-by-step explanation:

In the picture attached the histogram is shown. We can see that data is skewed to the right, so we have to use the five-number summary. The range of the data is 39 - 1 = 38 (subtraction of the maximum value to the minimum value); the median is (15 + 17)/2 = 16 (if you order the values, 15 and 17 are in the middle); quartile 1 is 9.25 and quartile 3 is 25.5 (see diagram of box and whisker attached), then half of the data are between those values.

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2 years ago
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