Answer:
The average value of 
over the interval ![[-2,5]](https://tex.z-dn.net/?f=%5B-2%2C5%5D)
is 
.
Step-by-step explanation:
Let suppose that function is continuous and integrable in the given intervals, by integral definition of average we have that:
(1)
(2)
By Fundamental Theorems of Calculus we expand both expressions:
(1b)
(2b)
We obtain the average value of over the interval ![[-2, 5]](https://tex.z-dn.net/?f=%5B-2%2C%205%5D)
by algebraic handling:
![F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)](https://tex.z-dn.net/?f=F%285%29%20-%20F%283%29%20%2B%5BF%283%29-F%28-2%29%5D%20%3D%2040%20%2B%20%28-30%29)
The average value of over the interval is .
Answer:
11x² - y
Step-by-step explanation:
Step 1: Write out expression
10x² - y + x²
Step 2: Combine like terms
11x² - y
That is simplest form.
the distance between points is:
d = 7.8 units
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
The ordered pairs are:
(x1, y1) = (- 3, -2)
(x2, y2) = (2,4)
By applying the formula we have:
d = root ((2 - (- 3)) ^ 2 + (4 - (- 2)) ^ 2)
d = root (61)
d = 7.8
Answer:
-1x+10
Step-by-step explanation:
<span><span>The </span>President of India<span> is
the formal </span>Head of State,
head of the executive and legislature of India and is the commander-in-chief of the Indian Armed Forces. Pranab Kumar Mukherjee<span> born on December 11, 1935
is the 13th and current </span>President of India, in
office since July 2012.</span>
