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3 years ago

5

Line m has no y-intercept, and its x-intercept is (3, 0). Line n has no x-intercept, and its y-intercept is (0, -4). The equatio

n of line m is , and the equation of line n is . NextReset

1 answer:

lora16 [44]3 years ago

4 0

Line m has no y int....so it does not cross the y axis....this means it is a vertical line with its equation being : x = 3.

line n has no x int...so it does not cross the x axis...means it is a horizontal line with its equation being : y = -4

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Which is the equation of a line that has a slope of 2 and contains the point (0,5)

riadik2000 [5.3K]

$\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{5})~\hspace{10em} slope = m\implies 2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-5=2(x-0) \\\\\\ y-5=2x\implies y=2x+5$

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3 years ago

PLEASE HELP ME WITH THIS

miv72 [106K]

Answer:

35/132

Step-by-step explanation:

The probability of selecting a boy for president is 7/12, the ratio of the number of boys to the number of candidates. Then the probability of selecting a girl for vice president is 5/11, the ratio of the number of girls to the remaining number of candidates. The joint probability is ...

(7/12)(5/11) = 35/132 . . . P(b=P&g=VP)

__

We can also look at this another way.

The number of ways two candidates can be selected from 12 is 12P2 = 132. The number of ways that the first can be a boy and the second can be a girl is (7)(5) = 35. Then the probability of a (BG) pair from the 12 candidates is 35/132.

_____

<em>Additional comment</em>

These numbers assume that selection is random and all possibilities are equally-likely. That is unlikely to be the case in an election.

7 0

3 years ago

What's the area of this

ozzi

5.5cm × 20cm = 110cm²
4.5cm × 20cm = 90cm²

110cm² + 90cm² = 200cm²

7 0

3 years ago

Please help! Will brainliest!

laila [671]

Answer:

a= 6-b ,,, a+b=6

a+b= -2a-3,,, 3a+b=-3

2a=-9,,, a= -9/ 2

b= 21/2

5 0

3 years ago

In the right ∆ABC, the hypotenuse AB = 17 cm. M is the midpoint of the hypotenuse. Find the legs if PAMC=32 cm and PBMC=25 cm

jeyben [28]

Answer:

The length of the legs is 8.64cm and 14.64cm respectively

Step-by-step explanation:

I've added an attachment to aid my explanation.

At different intervals, I'll be making reference to it.

Given

$AB = 17$

$PAMC = 32$

$PBMC = 25$

From the attachment, we have:

$y + z = AB$

Since, M is the Midpoint

$y = z = \½AB$

Substitute 17 for AB

$y = z = \½ * 17$

$y = z = 8.5$

Also, from the attachment

$v + x + z = PAMC$

$v + x + y = 32$

Substitute 8.5 for y

$v + x + 8.5 = 32$

$v + x = 32 - 8.5$

$v + x = 23.5$ --------- (1)

Also, from the attachment

$v + w + z = 25$

Substitute 8.5 for z

$v + w + 8.5 = 25$

$v + w = 25 - 8.5$

$v + w = 17.5$ ----------- (2)

Subtract (2) from (1)

$v - v + x - w = 23.5 - 17.5$

$x - w = 6$

Make x the subject

$x = 6 + w$

Apply Pythagoras Theorem:

We have that:

$AB^2 = AC^2 + BC^2$

The above can be replaced with

$17^2 = x^2 + w^2$ (see attachment)

$289 = x^2 + w^2$

Substitute 6 + w for x

$289 = (6 + w)^2 + w^2$

$289 = 36 + 12w + w^2 + w^2$

$289 - 36 = 12w + 2w^2$

$253 = 12w + 2w^2$

Reorder

$2w^2 + 12w - 253 = 0$

Solve using quadratic equation:

$w = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

Where

$a = 2$

$b = 12$

$c = -253$

$w = \frac{-12 \± \sqrt{12^2 - 4 * 2 * -253}}{2 * 2}$

$w = \frac{-12 \± \sqrt{144 + 2024}}{4}$

$w = \frac{-12 \± \sqrt{2168}}{4}$

$w = \frac{-12 \± 46.56}{4}$

Split:

$w = \frac{-12 + 46.56}{4}$ or $w = \frac{-12 - 46.56}{4}$

$w = \frac{34.56}{4}$ or $w = \frac{-58.56}{4}$

$w = 8.64$ or $w = -14.64$

But length can't be negative

So:

$w = 8.64$

Recall that: $x = 6 + w$

$x = 6 + 8.64$

$x = 14.64$

<em>Hence, the length of the legs is 8.64cm and 14.64cm respectively</em>

5 0

3 years ago