F(x)= ∫ln²x/x dx= ∫ln²xd(lnx) cause d(lnx)= (lnx)'dx=1/x dx
= ln³x/3 +C with C is constant
In addition, we have f(2)=6, so we have 6=ln³2/3+C
or C= 6- <span>ln³2/3
And f(x)= </span>ln³x/3+ <span> 6- </span><span>ln³2/3</span>
The GCF of 36 and 90 is 18.
Answer:
D. 1.38
Step-by-step explanation:
To compare numbers, start with the left side.
You are comparing these numbers with 1.32:
A.1.02
B.1.23
C.1.31
D.1.38
Start with the leftmost digit, the 1. All numbers start with 1, so up to the units place, they are all the same. See below.
1.32
A. 1.02
B. 1.23
C. 1.31
D. 1.38
Now compare the next digit which is the tenths place.
1.32
A. 1.02
B. 1.23
C. 1.31
D. 1.38
Above, the number 1.32 has a 3 in the tenths place. 3 is greater than 0 and than 2, so options A and B are less than 1.32 and are eliminated.
1.32
C. 1.31
D. 1.38
Now we compare the digits in the hundredths place shown just above. 2 is greater than 1, but it is less than 8, so we eliminate option C.
Answer: D. 1.38
4/32 = x/100
answer: x = 12.5
