Step-by-step explanation:
Answer:
Step-by-step explanation:
Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
He has a total of 7 Boards. he has 3 boards of his own and then you add the 4 additional boards that he has
Shifting a circle results to changes in the coordinates of the circle. For instance, if the coordinates of the center of the circle is taken to be (0,0), the new coordinates will be [(0+5),(0+2)] after shifting. The equation of the circle will also change with the same margin.
That is, the new equation will be;
(5+x)^2+(2+y)^2 =19
Notice, only the coordinates changes.
