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Sergeeva-Olga [200]
3 years ago
15

How many grams of naoh would react with 507 g fecl2 in the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl?

Chemistry
2 answers:
rosijanka [135]3 years ago
7 0
<span>Answer: Correct answer is 507g FeCl2 x (1 mol FeCl2 / 126.8 g FeC2) x (1 mol Fe(OH)2 / 1 mol FeCl2) x (89.8 g Fe(OH)2/ 1 mol Fe(OH)2) = 359 g Fe(OH)2.</span>
Vedmedyk [2.9K]3 years ago
3 0

Answer:320 g on apex

Explanation:

I just did it lol

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How many hydrogen atoms are in the compound represented by the following bond-line drawing?<br> ОН
Ganezh [65]

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Explanation:

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A car traveling north with a velocity of 30 m/sec slows down to a velocity of 10 m/sec
hoa [83]

Answer:

-2m/s/s

Explanation:

Acceleration = change in speed / change in time

Change in speed = final speed - initial speed

In this case the change in speed was 10m/s - 30m/s = -20m/s

And change in time was 10 sec (within 10 sec)

Therefore acceleration = -20/10 = -2m/s/s

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Hope this helped!

4 0
4 years ago
What is the pH of a mixture of 0.042 M NaH2PO4 and 0.058 M Na2HPO4? Hint: The pKa of phosphate is 6.86.
AlekseyPX

Answer:

The pH value of the mixture will be 7.00

Explanation:

Mono and disodium hydrogen phosphate mixture act as a buffer to maintain pH value around 7. Henderson–Hasselbalch equation is used to determine the pH value of a buffer mixture, which is mathematically expressed as,

pH=pK_{a} + log(\frac{[Base]}{[Acid]})

According to the given conditions, the equation will become as follow

pH=pK_{a} + log(\frac{[Na_{2}HPO_{4} ]}{[NaH_{2}PO_{4}]})

The base and acid are assigned by observing the pKa values of both the compounds; smaller value means more acidic. NaH₂PO₄ has a pKa value of 6.86, while Na₂HPO₄ has a pKa value of 12.32 (not given, but it's a constant). Another more easy way is to the count the acidic hydrogen in the molecular formula; the compound with more acidic hydrogens will be assigned acidic and vice versa.

Placing all the given data we obtain,

pH=6.86 + log(\frac{0.058}{0.042})

pH=7.00

5 0
4 years ago
Calculate how many moles of potassium (K) are present in a sample of 8.12x10^23 atoms of K​
Alona [7]

Answer:

1.35 moles

Explanation:

Calculate how many

of potassium (K) are present in a sample of 8.12x10^23 atoms of K​

6.02 X 10^23 atoms are 1 mole.  how many 6.02 X 10^23 are in

8.12 X 10^23

divide 8.12 X 10^23 into sets of 6.02 X 10^23

(8.12 X 10^23)/(6.02 X 10^23) =1.35 moles

4 0
3 years ago
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