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JulijaS [17]
3 years ago
5

How many hydrogen atoms are in the compound represented by the following bond-line drawing? ОН

Chemistry
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

Theres no drawing

Explanation:

Show drawing

You might be interested in
How many moles of Fluorine (F2) are<br><br> needed to completely react 8.0<br><br> moles of NF3?
Anna [14]

Answer:

12 moles of F₂

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3F₂ —> 2NF₃

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Finally, we shall determine the number of mole of F₂ needed to produce 8 moles of NF₃. This can be obtained as illustrated below:

From the balanced equation above,

3 moles of F₂ reacted to produce 2 moles of NF₃.

Therefore, Xmol of F₂ will react to produce 8 moles of NF₃ i.e

Xmol of F₂ = (3 × 8)/2

Xmol of F₂ = 12 moles

Thus, 12 moles of F₂ is needed for the reaction.

8 0
3 years ago
Complete the mechanism for the reaction by adding the missing curved arrows, atoms, bonds, charges, and nonbonding electron pair
Keith_Richards [23]

Answer:

See explanation below

Explanation:

In picture 1 attached, we have the starting structure. In picture 2, you have the answer for this.

Basically this is an acid base reaction to promove then, a condensation of the molecule.

In the first step, the carbonile substract a H atom from the HCl. Then, by resonance the OH+, pass the charge to the carbon, which is tertiary and can be easily stabilized. Now, after this, the Chlorine substract an Hydrogen to get a double bond on the carbon with the charge, and this be stable. Now, a second molecule of benzaldehyde reacts with this, so we can have a condensation product.

See picture 2 for complete mechanism.

4 0
3 years ago
Which bond does this picture best represent?
ddd [48]

Answer:

C is the answer they are looking for but clearly the truth is D

Explanation:

4 0
3 years ago
At what substrate concentration would an enzyme with a K_cat of 30.0 s⁻¹ and a Km of 0.0050 M operate at one-quarter of its maxi
Umnica [9.8K]

Answer:

The correct answer is option B.

Explanation:

Michaelis–Menten 's equation:

v=V_{max}\times \frac{[S]}{(K_m+[S])}=k_{cat}[E_o]\times \frac{[S]}{(K_m+[S])}

V_{max}=k_{cat}[E_o]

v = rate of formation of products

[S] = Concatenation of substrate = ?

[K_m] = Michaelis constant

V_{max}= Maximum rate achieved

k_{cat} = Catalytic rate of the system

E_o = initial concentration of enzyme

We have :

v=\frac{V_{max}}{4}

[S] =?

K_m=0.0050 M

v=V_{max}\times \frac{[S]}{(K_m+[S])}

\frac{V_{max}}{4}=V_{max}\times \frac{[S]}{(0.0050 M+[S])}

[S]=\frac{0.005 M}{3}=1.7\times 10^{-3} M

So, the correct answer is option B.

8 0
3 years ago
Thymine is always joined to
WARRIOR [948]

Adenine.

Thymine always pairs with Adenine while Cytosine always pairs with Guanine on DNA strands.

Hope this helps!

4 0
4 years ago
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