All categories

3 years ago

Circumference involves u its or squate units

Mathematics

1 answer:

kodGreya [7K]3 years ago

5 0

Circumference has the answer in square units.

You might be interested in

May someone help me with this?

Colt1911 [192]

Answer:

Step-by-step explanation:

4 0

3 years ago

The y -intercept of the line whose equation is x - y = -1 is<br><br> 0<br> 1<br> -1

Feliz [49]

Answer:

Step-by-step explanation:

y- intercept occurs at x= 0. Thus, the y-intercept of a line can be found by substituting x= 0 into it's equation.

x -y= -1

When x= 0,

0 -y= -1

-y= -1

Divide both sides by -1:

y= -1 ÷(-1)

y= 1

Thus, the y-intercept is 1.

8 0

2 years ago

3. Cuál de las siguientes fracciones NO es equivalente a 6/11:

Readme [11.4K]

Answer:

C no es equivalente a 6/11.

Step-by-step explanation:

24/42 no es equivalente a 6/11 porque, cuando se simplifica, no es igual a este número. Si usamos el número 6 para simplificar, la respuesta a 24/42 sería 4/7, que no es igual a 6/11.

7 0

3 years ago

Read 2 more answers

Which equation represents the polar form of x² + (y + 4)² = 16?

Paraphin [41]

$x^2+y^2=r^2\hspace{5em}x=r\cos(\theta )\hspace{5em}y=r\sin(\theta ) \\\\[-0.35em] ~\dotfill\\\\ x^2+(y+4)^2=16\implies x^2+\stackrel{binomial~expansion}{y^2+8y+16}=16 \\\\\\ \underset{x^2+y^2}{r^2} + 8(~\underset{8y}{r\sin(\theta )}~)=16-16\implies r^2+8r\sin(\theta)=0 \\\\\\ r^2=-8r\sin(\theta )\implies \cfrac{r^2}{r}=-8\sin(\theta )\implies r=-8\sin(\theta )$

3 0

2 years ago

Pre image ABCD was dilated to produce image A’B’C’D why is the scale factor from the pre image? Enter your answer in the box as

shepuryov [24]

The scale factor of the dilation from ABCD to A′B′C′D′ is 3.

Step-by-step explanation:

Step 1:

In the pre-image ABCD, the length of one of the sides is given as 14 units.

For the other shape A′B′C′D′, the same side as the previous shape is given as 8 units.

Step 2:

To determine the scale factor, we divide the measurement after scaling by the same measurement before scaling.

In this case, it is the given length of the sides CD and C′D′.

So the scale factor = $\frac{C^{1} D^{1} }{CD} = \frac{8}{14} = \frac{4}{7} .$

So the shape ABCD is dilated by a scale factor of $\frac{4}{7}$ to produce the shape A′B′C′D′.

7 0

3 years ago